Answer:
-9x^9y^5
Step-by-step explanation:
Do the multiply first:
-16x^9y^5+7x^9y^5
=x^9y^5(-16+7)
=-9x^9y^5
I think it is C.Skewed right.
Check whether it is possible to have a triangle with the given side lengths for example 7,9,13 then add any two sides and see if it is greater than the other side. Example the sum of 7 and 9 is 16 and 16 is greater than 13
Use the Pythagorean theorem. The equation for this right triangle would be a^2+b^2=c^2. Since you have one leg and the hypotenuse, you can plug these into the equation. It would be 7^2+b^2=12^2. Do the exponents. You will get 49+b^2=144. You need to get b by itself so subtract each side by 49. You get the equation b^2=95. Square root each side to get b=9.746. This rounds to 9.7. So the answer is A. Hope this helps! ;)
That means:
1) you cannot factorize it, or
2) the binomial is not the right one to be the quotient or
3) the roots of the binomial are not the roots of the polynomial
