P1 has a clock rate of 4 GHz, average CPI of 0.9, and requires the execution of 5.0E9 instructions.P2 has a clock rate of 3 GHz,
an average CPI of 0.75, and requires the execution of 1.0E9 instructions.1.12.1 [5] <§§1.6, 1.10> One usual fallacy is to consider the computer with thelargest clock rate as having the largest performance. Check if this is true for P1 and P2.1.12.2 [10] <§§1.6, 1.10> Another fallacy is to consider that the processor executingthe largest number of instructions will need a larger CPU time. Considering thatprocessor P1 is executing a sequence of 1.0E9 instructions and that the CPI ofprocessors P1 and P2 do not change, determine the number of instructions that P2can execute in the same time that P1 needs to execute 1.0E9 instructions.1.12.3 [10] <§§1.6, 1.10> A common fallacy is to use MIPS (millions ofinstructions per second) to compare the performance of two different processors,and consider that the processor with the largest MIPS has the largest performance.Check if this is true for P1 and P2.1.12.4 [10] <§1.10> Another common performance figure is MFLOPS (millionsof floating-point operations per second), defined asMFLOPS = No. FP operations / (execution time × 1E6)but this figure has the same problems as MIPS. Assume that 40% of the instructionsexecuted on both P1 and P2 are floating-point instructions. Find the MFLOPSfigures for the programs.
1 answer:
You might be interested in