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TEA [102]
3 years ago
7

HELP PLZ GIVE A BRAINLIST

Mathematics
1 answer:
lys-0071 [83]3 years ago
6 0

Answer:

\displaystyle [2, -3]

Step-by-step explanation:

{2x - 3y = 13

{x + 2y = −4

⅔[2x - 3y = 13]

{1⅓x - 2y = 8⅔

{x + 2y = −4

____________

\displaystyle \frac{2\frac{1}{3}x}{2\frac{1}{3}} = \frac{4\frac{2}{3}}{2\frac{1}{3}}

\displaystyle x = 2[Plug this back into both equations above to get the y-coordinate of −3]; \displaystyle -3 = y

* This is using the Elimination Method.

I am joyous to assist you anytime.

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Which ordered pair is a solution of the inequality? y is greater than or equal to 4x-5
lesya692 [45]
(1,1) -->> 1 >= 4(1) - 5 -->> 1 >= 4-5 -->> 4 >= -1
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3 years ago
Which of the following phrases can be used to represent -11? the opposite of -11 eleven greater than zero eleven below zero posi
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Answer:

the opposite of -11 eleven greater than zero eleven below zero positive eleven

Step-by-step explanation:

5 0
3 years ago
Find the other two vertices of a square with one vertex (0, 0) and another vertex (4, 2). Can you find another answer?
Margarita [4]

It is given that two vertices of square are (0,0) and (4,2).

Now the problem is that you haven't given that whether these two vertices are adjacent vertices or opposite vertices of the square.

1. By Supposing that these two are adjacent vertices of Square

The third vertex will be at (-4,2) which lies in third quadrant.

Suppose the coordinate of fourth vertex be (x,y).

Mid point of line joining (4,2) and (-4,2) is{ [4+(-4)]/2,(2+2)/2} is (0,2).

Mid point of line joining (x,y) and (0,0) is (x/2,y/2).

Since diagonals of square bisect each other,

∵ x/2=0

⇒x=0

and

y/2=2

⇒y=4

So, The Coordinate of  fourth vertex is (0,4).

Now coming back to second condition if these are two opposite vertex of Square.

Let the third coordinate be (a,b).

Length of diagonal=\sqrt{(4-0)^2+(2-0)^2}=\sqrt20=2\sqrt5

Now,let side of Square be A.

Then length of Diagonal of square =√2 A

⇒√2 A=2√5

⇒A =√10

As third vertex is (a,b).

Using distance formula

a² + b²=10  -------------(1)

(a-4)²+ (b-2)²=10  --------------(2)

Solving expression (1) and (2), we get

⇒a²+ b²=(a-4)² +(b-2)²

⇒2a + b =5

⇒b=5-2a

Putting the value of b in (1),we get

⇒a² +(5-2a)²=10

⇒a²+25+4a²-20a =10

⇒5a²-20a+15=0

⇒a² - 4a + 3=0

Splitting the middle term,we get

⇒(a-3)(a-1)=0

⇒a=3  ∧  a=1

we get b=5-2×1=3 and b=5-2×3=5-6=-1

So,the other vertex are (1,3) and(3,-1).





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3 years ago
If the graph of an equation is symmetric with respect to the y-axis and 6 is an x-intercept, name another x-intercept
givi [52]
-6 because for every value (x,y) there is another value (-x,y) so for the value (6,0) there must also be a value (-6,0). That is what the definition of y-axis symmetry is, it is also known as being an "even" function if it has this type of symmetry. Look at the graph of y=(x^2)-36 to see how this works.
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Six over ten >_______> one over two
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Six over ten over one over two is 0.3
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