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Butoxors [25]
3 years ago
13

PLS HELP ME :(

Mathematics
1 answer:
Virty [35]3 years ago
8 0

Answer:

2438.4

Step-by-step explanation:

multiply 96 by 25.4

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25 points!! please answer
melomori [17]

ac is the answer

hope that helps

6 0
3 years ago
Read 2 more answers
What is 0.05 repeating as a fraction ?
grin007 [14]
This is the best I got Require to make 2 equations with the same repeating part and subtract them to eliminate the repeating part.

begin by letting x = 0.5555555................. (1)

To obtain the same repeating part after the decimal point need to multiply by 10

hence 10x = 5.555555........................(2)

It is important to obtain 2 equations in x, where the recurring part after the decimal points are exactly the same.

now subtract (1) from (2) to obtain fraction

(2) - (1) : <span>9x=5⇒x=<span><span>59</span></span></span>

8 0
3 years ago
Is this perpendicular, parallel, or neither?<br>y=4x+5 <br>2x+8y=16
ANEK [815]
Its perpendicular, if you need me to explain lmk
6 0
3 years ago
What is the probability that a random person who tests positive for a certain blood disease actually has the disease, if we know
xeze [42]

Answer:

Step-by-step explanation:

Hello!

Any medical test used to detect certain sicknesses have several probabilities associated with their results.

Positive (test is +) ⇒ P(+)

True positive (test is + and the patient is sick) ⇒ P(+ ∩ S)

False-positive (test is + but the patient is healthy) ⇒P(+ ∩ H)

Negative (test is -) ⇒ P(-)

True negative (test is - and the patient is healthy) ⇒ P(- ∩ H)

False-negative (test is - but the patient is sick) ⇒ P(- ∩ S)

The sensibility of the test is defined as the capacity of the test to detect the sickness in sick patients (true  positive rate).

⇒ P(+/S) =<u> P(+ ∩ S)  </u>

                    P(S)

The specificity of the test is the capacity of the test to have a negative result when the patients are truly  healthy (true negative rate)

⇒ P(-/H) =<u> P(- ∩ H)  </u>

                   P(H)

For this particular blood disease the following probabilities are known:

1% of the population has the disease: P(S)= 0.01

95% of those who are sick, test positive for it: P(+/S)= 0.95 (sensibility of the test)

2% of those who don't have the disease, test positive for it: P(+/H)= 0.02

The probability of a person having the blood sickness given that the test was positive is:

P(S/+)= <u> P(+ ∩ S)  </u>

                P(+)

The first step you need to calculate the intersection between both events + and S, for that you will use the information about the sickness prevalence in the population and the sensibility of the test:

P(+/S) =<u> P(+ ∩ S) </u>

                 P(S)

P(+/S)* P(S)  = P(+ ∩ S)  

P(+ ∩ S) = 0.95*0.01= 0.0095

The second step is to calculate the probability of the test being positive:

P(+)=  P(+ ∩ S) +  P(+ ∩ H)

Now we know that 1% of the population has the blood sickness, wich means that 99% of the population doesn't have it, symbolically: P(H)= 0.99

Then you can clear the value of P(+ ∩ H):

P(+/H) =<u> P(+ ∩ H) </u>

                 P(H)

P(+/H)*P(H)  = P(+ ∩ H)

P(+ ∩ H) = 0.02*0.99= 0.0198

Next you can calculate P(+):

P(+)=  P(+ ∩ S) +  P(+ ∩ H)= 0.0095 + 0.0198= 0.0293

Now you can calculate the asked probability:

P(S/+)= <u> P(+ ∩ S)  </u> =<u> 0.0095 </u>= 0.32

                P(+)        0.0293

I hope it helps!

                 

                 

6 0
3 years ago
A right angle triangle is shown with hypotenuse equal to 10 centimeters. An acute angle of the triangle is labeled as x degrees
Nostrana [21]

The Question is incomplete the Complete Question is

Look at the triangle: A right angle triangle is shown with hypotenuse equal to 10 centimeters. An acute angle of the triangle is labeled as x degrees. The side adjacent to the acute angle has length 6 centimeters and the side opposite to the acute angle has length 8 centimeters. What is the value of tan x°?

Answer:

Therefore the value of tan x is

\tan x=\dfrac{4}{3}

Step-by-step explanation:

Given:

hypotenuse = 10 cm'

side adjacent to the acute angle 'x' = 6 cm.

side opposite to the acute angle 'x' = 8 cm.

To Find:

tan x = ?

Solution:

In Right Angle Triangle , Tan Identity we have

\tan x= \dfrac{\textrm{side opposite to angle x}}{\textrm{side adjacent to angle x}}

Substituting the values we get

\tan x= \dfrac{8}{6}=\dfrac{4}{3}

Therefore the value of tan x is

\tan x=\dfrac{4}{3}

4 0
3 years ago
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