Which value of y makes the equation true. 72=y over6
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Given a right triangle with base, b and height, h with the angle opposide side h as θ.
The area of a triangle is given by
But,
Therefore, the area of the triangle in terms of <span>b and θ only is given by
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The area of a triangle is given by
But,
Therefore, the area of the triangle in terms of <span>b and θ only is given by
The vertex-form equation is
y = a(x+1)² -16
Putting in the y-intercept values, we have
-15 = a(0+1)² -16
1 = a . . . . . . . . . . . add 16
Then the x-intercepts can be found where y=0.
0 = (x+1)² -16
16 = (x+1)²
±4 = x+1
x = -1 ± 4 = {-5, 3}
y = a(x+1)² -16
Putting in the y-intercept values, we have
-15 = a(0+1)² -16
1 = a . . . . . . . . . . . add 16
Then the x-intercepts can be found where y=0.
0 = (x+1)² -16
16 = (x+1)²
±4 = x+1
x = -1 ± 4 = {-5, 3}