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yarga [219]
3 years ago
8

Parth created a Box-and-Whisker Plot to show the average weight of the fish he caught over the weekend. What information from th

e 1st Quartile does the graph give you?
A. Three fourths of the fish he caught were larger than 22 pounds.
B. The average weight of the fish he caught was 40 pounds.
C. Three fourths of the fish he caught were less than 22 pounds.
D. The largest fish he caught was 63 pounds.
Mathematics
1 answer:
Zepler [3.9K]3 years ago
6 0

The 1st Quartile that the Box-and-Whisker Plot shows tells us that: <em>A. Three fourths of the fish he caught were larger than 22 pounds.</em>

Recall:

  • In a Box-and-Whisker Plot, about 25% of the data will be below the first quartile while 75% will be above the first quartile, that is Three fourths of the data will be above the first quartile and one-fourths will be below the first quartile.

Thus, the given Box-and-Whisker Plot as shown in the diagram below shows that the first quartile is 22 pounds.

Therefore, the 1st Quartile that the Box-and-Whisker Plot shows tells us that: <em>A. Three fourths of the fish he caught were larger than 22 pounds.</em>

Learn more about Box-and-Whisker Plot on:

brainly.com/question/12343132

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Stolb23 [73]

Answer:

$1092671.191

Step-by-step explanation:

<u>Cálculo de Areas</u>

El área de un círculo de radio r se obtiene con la fórmula:

A_c=\pi r^2

El área de un triángulo de base b y altura h, perpendicular a la base es:

A_t=\frac{bh}{2}

Si el triángulo es rectángulo, b y h son los catetos

El solar tiene una forma tal como se ilustra en la figura anexa. Para averiguar el costo del abono y del techo, debe calcularse primero el área total a cultivar. Primero se determina el área de 3/4 de círculo de radio 5.9 metros

A_c=\frac{3}{4}\pi r^2

A_c=\frac{3}{4}\pi (5.9)^2

A_c=82.0191302\ m^2

Por su parte, el triángulo mostrado, tiene ambos catetos iguales al radio de círculo, por lo que su área será

A_t=\frac{r^2}{2}

A_t=\frac{(5.9)^2}{2}

A_t=17.405\ m^2

El área total del solar es la suma de ambas:

A_s=82.0191302\ m^2+17.405\ m^2

A_s=99.4241302\ m^2

El metro cuadrado de abono cuesta $8016. El costo de abono es

C_a=99.4241302\ m^2*8016=\$796983.8277

El metro cuadrado de techo cuesta $2974. El costo del techo es

C_t=99.4241302\ m^2*2974=\$295687.3632

El costo total es la suma de los dos anteriores:

Total=\$796983.8277+\$295687.3632

Total=\$1092671.191

El valor total a intervenir para la adecuación del solar es $1092671.191

7 0
3 years ago
Is the function given by ​f(x)equalsleft brace Start 2 By 2 Matrix 1st Row 1st Column one fourth x plus 1 comma 2nd Column for x
MArishka [77]

Answer:

C. The given function is continuous at x=4 because the limit is 2.

Step-by-step explanation:

Given the function:

f(x)=\left\{\begin{array}{ccc}\frac{1}{4}x+1 &x\leq 4\\4x-11&x>4\end{array}\right

We are to determine if the function is continuous at x=4.

For a function to be continuous  at some value c in its domain:

  • f(c) must be defined.
  • Lim_{x \to c}$ f(x) must exist.
  • f(c)=Lim_{x \to c}$ f(x)

Now: at x=4

  • f(4)=\dfrac{1}{4}*4+1=2
  • Lim_{x \to 4}f(x)=2

Since the two values are the same, we say that f(x) is continuous at x=4.

The correct option is C.

5 0
3 years ago
Compare the values of the underlined digits 6,300 and 530, the 3 is underlined in both numbers
cricket20 [7]
6300 the three is 300 and in 530 the 3 is. 30
7 0
3 years ago
Read 2 more answers
What is the surface area of the cylinder with height 5 m and radius 8 m?
Vinvika [58]

Answer: ur welcome ;)

20

Step-by-step explanation:

5 times 8 is 40. 40 divided by 2 is 20.

6 0
3 years ago
What is 6 + (-4 3/4) + (-2 1/8)=7/8
mihalych1998 [28]
Conversion a mixed number -4 3/
4
to a improper fraction: -4 3/4 = -4 3/
4
= -4 · 4 + (-3)/4
= -16 + (-3)/4
= -19/4
Add: 6 + (-19/4)= 6/1
+ (-19/4) = 6 · 4/1 · 4
+ (-19)/4
= 24/4+ (-19/4)=24 + (-19)/4
= 5/4

2 1/8 = -2 1/8
= -2 · 8 + (-1)/8
= -16 + (-1)/8
= -17/8
Add: the result of step No.
2 + (-17/8) = 5/4+ (-17/8) = 5 · 2/4 · 2+ (-17)/8= 10/8+ (-17/8) = 10 + (-17)/8= -7/8
3 0
3 years ago
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