All categories

4 years ago

Convert 2.1 x 10^5 to ordinary form

Mathematics

1 answer:

Degger [83]4 years ago

8 0

Answer:

2.1 x 10^5 = 210,000.

Step-by-step explanation:

Convert 2.1 x 10^5 to ordinary form

10^5 = 100000

2.1 = 21/10

Thus.

2.1 x 10^5 = 21/10 * 100000 = 210,000

Ordinary form of 2.1 x 10^5 is 210,000.

You might be interested in

Naval intelligence reports that 4 enemy vessels in a fleet of 17 are carrying nuclear weapons. If 9 vessels are randomly targete

icang [17]

Answer:

0.7588 = 75.88% probability that more than 1 vessel transporting nuclear weapons was destroyed

Step-by-step explanation:

The vessels are destroyed without replacement, which means that the hypergeometric distribution is used to solve this question.

Hypergeometric distribution:

The probability of x successes is given by the following formula:

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

In which:

x is the number of successes.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

In this question:

Fleet of 17 means that $N = 17$

4 are carrying nucleas weapons, which means that $k = 4$

9 are destroyed, which means that $n = 9$

What is the probability that more than 1 vessel transporting nuclear weapons was destroyed?

This is:

$P(X > 1) = 1 - P(X \leq 1)$

In which

$P(X \leq 1) = P(X = 0) + P(X = 1)$

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

$P(X = 0) = h(0,17,9,4) = \frac{C_{4,0}*C_{13,9}}{C_{17,9}} = 0.0294$

$P(X = 1) = h(1,17,9,4) = \frac{C_{4,1}*C_{13,8}}{C_{17,9}} = 0.2118$

Then

$P(X \leq 1) = P(X = 0) + P(X = 1) = 0.0294 + 0.2118 = 0.2412$

$P(X > 1) = 1 - P(X \leq 1) = 1 - 0.2412 = 0.7588$

0.7588 = 75.88% probability that more than 1 vessel transporting nuclear weapons was destroyed

8 0

3 years ago

Answer this question pls!!

Dvinal [7]

Answer:

3.5

Step-by-step explanation:

5 0

3 years ago

What is the solution set of these system5x-2y=17 and 4x-7=13?

MatroZZZ [7]

Answer:

x=5

y=4

Step-by-step explanation:

Step 1:

Let us solve for x using the $4x-7=13$ equation by isolating terms containing the variable:

$4x-7=13\\4x=20\\\fbox{x=5}$

Great! x is 5... let's find y.

Step 2:

Since we know the value of x, we can use what we know to find y using the other equation:

$5x-2y=17\\$

Given that x=5, we can replace x with 5.

$5*5-2y=17\\25-2y=17\\2y=8\\\\\fbox{y=4}$

I hope this helps! Let me know if you have any questions :)

3 0

3 years ago

How to use inverse cosin

Alecsey [184]

Answer:

sec

Step-by-step explanation:

1/cosin = sec or cosin^-1

4 0

2 years ago

How many hours is 10 miles?

Aleksandr-060686 [28]

Depends on the speed

7 0

3 years ago