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chubhunter [2.5K]

3 years ago

10

10 < 3x + 19 Help ASAP time is running out !

2 answers:

SashulF [63]3 years ago

6 0

Answer:

-3 < x

Step-by-step explanation:

Subtract 19 both sides, divide by 3

timurjin [86]3 years ago

5 0

Answer:

-3<x

Step-by-step explanation:

10 < 3x + 19

10 - 19 < 3x

-9 < 3x

-9/3 < x

-3 < x

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What is the balance on a deposit of $1,150 that earns 9% interest compounded annually for 2 years

igor_vitrenko [27]

Step One: Calculate interest.

$1150*0.09=103.5$

Step Two: Calculate the amount at the end of the first year.

$1150+103.5=1253.5$

Step Three: Calculate the amount at the end of the second year. This will be your final answer.

$1253.5+103.5=1357$

$1357 balance

3 0

3 years ago

Find the first three iterates of the function f(z) = z2 + c with a value of c = 2 - 3i and an initial value of z0 = 1 + 2i.

Artist 52 [7]

Answer:

C

Step-by-step explanation:

We have: (I rewrote the function)

$f(z_n)={z_{n-1}} ^2+c$

Given that:

$\displaystyle c=2-3i \text{ and } z_0 = 1 + 2 i$

The first iterate will be:

$\displaystyle \begin{aligned} f(z_1)&=(z_0)^2+c \\ &=(1+2i)^2+(2-3i) \\ &= (1+4i+4i^2)+(2-3i) \\ &=1+4i-4+2-3i \\ &=-1+i \end{aligned}$

The second iterate will be:

$\begin{aligned}f(z_2) &=(z_1)^2+c\\ &=(-1+i)^2+(2-3i) \\&= (1-2i+i^2)+(2-3i) \\&=1-2i-1+2-3i \\&=2-5i \end{aligned}$

And the third iterate will be:

$\begin{aligned} f(z_3)&=(z_2)^2+c\\ &=(2-5i)^2+(2-3i) \\ &=(4-20i+25i^2)+(2-3i) \\ &=4-20i-25+2-3i \\ &=-19-23i \end{aligned}$

Hence, our answer is C.

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2 years ago

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SpyIntel [72]

Answer:

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Step-by-step explanation:

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2 years ago

Can someone help me with this question

Vera_Pavlovna [14]

Answer:

200 kids

Step-by-step explanation:

4 0

2 years ago

What is the explicit formula for the sequence 7,2,-3,-8,-13

eduard

You could say that a(n) = 12 - 5n .

Then ...

a(1) = 12 - 5 = 7
a(2) = 12 - 10 = 2
a(3) = 12 - 15 = -3
and so on.
So it seems to work.

8 0

2 years ago

Read 2 more answers