All categories

2 years ago

What are all shapes a all right angle rectangle can be

Mathematics

1 answer:

Gelneren [198K]2 years ago

4 0

Answer:square, triangle, rectangle

Step-by-step explanation:

You might be interested in

Write a number in which the digit 3 is ten times the value of the digit 3 in 9.431

IgorC [24]

Answer:

Step-by-step explanation:

One number would be

9.31

The 3 in this number is 3/10

The 3 in the given number is 3/100

3/10 is 10 times bigger than 3/100

3/10 = 0.3

3/100 = 0.03

0.03 * x = 0.3 Divide both sides by 0.03

0.03/0.03 x = 0.3/0.03

x = 10

6 0

2 years ago

Can someone please help me with my maths question

DIA [1.3K]

Answer:

$a. \ \dfrac{625 \cdot m}{27 \cdot n^{11}}$

$b. \ \dfrac{x^{3 \cdot m - 2}}{y^{ 3 + n}}$

Step-by-step explanation:

The question relates with rules of indices

(a) The give expression is presented as follows;

$\dfrac{m^3 \times \left (n^{-2} \right )^4 \times (5 \cdot m)^4}{\left (3 \cdot m^2 \cdot n \right )^3}$

By expanding the expression, we get;

$\dfrac{m^3 \times n^{-8} \times 5^4 \times m^4}{\left 3^3 \times m^6 \times n^3}$

Collecting like terms gives;

$\dfrac{m^{(3 + 4 - 6)} \times 5^4}{ 3^3 \times n^{3 + 8}} = \dfrac{625 \cdot m}{27 \cdot n^{11}}$

$\dfrac{m^3 \times \left (n^{-2} \right )^4 \times (5 \cdot m)^4}{\left (3 \cdot m^2 \cdot n \right )^3}= \dfrac{625 \cdot m}{27 \cdot n^{11}}$

(b) The given expression is presented as follows;

$x^{3 \cdot m + 2} \times \left (y^{n - 1} \right )^3 \div (x \cdot y^n)^4$

Therefore, we get;

$x^{3 \cdot m + 2} \times \left (y^{n - 1} \right )^3 \times x^{-4} \times y^{-4 \cdot n}$

Collecting like terms gives;

$x^{3 \cdot m + 2 - 4} \times \left (y^{3 \cdot n - 3 -4 \cdot n}} \right ) = x^{3 \cdot m - 2} \times \left (y^{ - 3 -n}} \right ) = x^{3 \cdot m - 2} \div \left (y^{ 3 + n}} \right )$

$x^{3 \cdot m - 2} \div \left (y^{ 3 + n}} \right ) = \dfrac{x^{3 \cdot m - 2}}{y^{ 3 + n}}$

$x^{3 \cdot m + 2} \times \left (y^{n - 1} \right )^3 \times x^{-4} \times y^{-4 \cdot n} =\dfrac{x^{3 \cdot m - 2}}{y^{ 3 + n}}$

4 0

2 years ago

Cos90degrees cos30 degrees + sec-squared45degrees sin30degrees - cos270degrees sin180degrees

yawa3891 [41]

Step-by-step explanation:

$\cos 90 \cos 30 + \sec^2 45 \sin 30 - \cos 270 \sin 180$

But we know that

$\cos 90 = \cos 270 = \sin 180 = 0$

and

$\sin 30 = \dfrac{\sqrt{3}}{2} \:\:\text{and}\:\: \sec 45 = \sqrt{2}$

so this leaves us with just

$\sec^2 45 \sin 30 = (\sqrt{2})^2 \left(\dfrac{\sqrt{3}}{2} \right)= \sqrt{3}$

6 0

2 years ago

Plsssssssssss helpp reeeeeeee

valentina_108 [34]

Answer:

102.62

Step-by-step explanation:

I converted everything to inches and then solved for x by putting 58 in. over 66 in. (the girls shadow in in.) and the X in. over 1500 in. I cross multiplied (58 x 1500 and 68 x X) and then divided 68 by the result of 58 x 1500.

4 0

2 years ago

Read 2 more answers

Find the missing side lengths?

scZoUnD [109]

answer of this question

7 0

2 years ago