Assume that passwords are selected from four-character combinations of 26 alphabeticcharacters. Assume that an adversary is able
1 answer:
You might be interested in
Answer:
Check the explanation
Explanation:
#include <stdio.h>
#include <string.h>
#include <stdlib.h>
#define MAX_LIMIT 50
int checkComma(char *input)
{
int flag = 0;
for(int i = 0; i < strlen(input); i++)
{
if(input[i] == ',')
{
flag = 1;
break;
}
}
return flag;
}
int main(void)
{
char input[MAX_LIMIT];
char *words[2];
char delim[] = ", ";
printf("\n");
do
{
printf("Enter input string: ");
fgets(input, MAX_LIMIT, stdin);
size_t ln = strlen(input) - 1;
if (*input && input[ln] == '\n')
input[ln] = '\0';
if(strcmp(input, "q") == 0)
{
printf("Thank you...Exiting\n\n");
exit(1);
}
else
{
if(checkComma(input) == 0)
{
printf("No comma in string.\n\n");
}
else
{
char *ptr = strtok(input, delim);
int count = 0;
while(ptr != NULL)
{
words[count++] = ptr;
ptr = strtok(NULL, delim);
}
printf("First word: %s\n", words[0]);
printf("Second word: %s\n\n", words[1]);
}
}
}while(strcmp(input, "q") != 0);
return 0;
}
Kindly check the attached image below for the output.
