<u>C++ program to print the digit without a comma </u>
#include<iostream>
#include<string>
using namespace std;
void commaremoval(string num) /*Defining function commaremoval with parameter num of string type*/
{
string s=num;
for(int i=0; i< s.length();i++)
{
if(s[i]!=',')
/*Checking whether the string doesn't contain ' ,' */
cout<<s[i]; //Printing Output without comma
}
}
//driver function
int main()
{
string num;
cout<<"Enter a digit between 1,000 and 999,999:"<<endl;
/*taking input from user*/
cin>>num;
commaremoval(num);
//calling function
return 0;
}
<u>Output</u>
Enter a digit between 1,000 and 999,999: 22,343
22343
Answer:
The correct answer to this question is "true".
Explanation:
In a layered operating system, all the layers defined individually and communicate with each other when required. It is also easier to create, manage and update the system. If we change in one layer. The Changement has done in only a specific layer it does not affect any other layers. In this operating system, there are 6 layers.
In the monolithic system. It works on the kernel space. That increases the size of the operating system and kernel. It is different than the microkernel system. In the monolithic system, there are 3 layers.
If we assign any work to both, So the 6 layers will take more time to do that work. when that 3 layers take less time to do that work.
that's way layered operating performance is slower than the monolithic system.
Answer:
B) The charge-coupled device
Explanation:
Around 1964 the first CMOS (Complementary Metal Oxide Semiconductor) circuits were developed. This would be the "embryo" of the Charge-coupled Device (CCD), which equips current digital cameras and who is responsible for capturing images.
CMOS is a small circuit that uses very little energy and stores information such as date, time and system configuration parameters.
The first CCD was developed in 1969 and it is still used today in many portable devices and computers.
Answer:
void print_popcorn_time(int bag_ounces){
if(bag_ounces < 3){
cout<<"Too small"<<endl;
}else if(bag_ounces > 10){
cout<<"Too large"<<endl;
}else{
cout<<(6 * bag_ounces)<<"seconds"<<endl;
}
}
Explanation:
The function is the block of the statement which performs the special task.
For checking the condition in the program, the if-else statement is used.
It can check the condition one or two but if we want to check the more than two different conditions then the continuous if-else statement is used.
syntax of continuous if else:
if(condition){
statement;
}else if(condition)
statement;
}else{
statement;
}
In the question, there are three conditions;
1. bag_ounces is less than 3
2. bag_ounces greater than 10
3. else part.
we put the condition in the above if-else statement and print the corresponding message.
The right answer is A<span>.Active cell </span>
