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TEA [102]
3 years ago
9

Which of these descriptions does the equation 11x - 8 = 4 ​represent?

Mathematics
1 answer:
Musya8 [376]3 years ago
8 0
The answer to the question is B.
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What is the slope of (-2, -1) and (-5, -9)
djyliett [7]
8/3 pretty sure that’s the answer
5 0
2 years ago
What is the measurement<br> Or side rs
ANEK [815]
Sine 61 = RS / hypotenuse
RS = Sine 61 * hypotenuse
RS = 0.87462 * 8
RS = <span> <span> <span> 6.99696 </span> </span> </span>



3 0
2 years ago
Suppose a researcher is conducting a hypothesis test for a mean and finds a test statistic of z=2.3z=2.3 . Which of the choices
Galina-37 [17]

Answer:

Option c. The result is significant at the 0.020.02 level.

Step-by-step explanation:

We are given the following in the question:

We are conducting a one tailed hypothesis test with alternate hypothesis

H_A: \mu > \mu_0

The z test calculated for the same is

z=2.3

We calculate the p-value from the standard normal table.

p value = 0.010724 at 0.05 significance level.

The result is significant

p value = 0.010724 at 0.01 significance level.

The result is not significant

p value = 0.010724 at 0.02 significance level.

The result is significant at 0.02 significance level.

Thus, the correct answer is

Option c. The result is significant at the 0.020.02 level.

3 0
2 years ago
I need an answer to this asap... please ....just number 3
Agata [3.3K]

Answer:

hence cos ( 2 A ) = cos 2 A − ( 1 − cos 2 A ) = 2 cos 2 A − 1


Step-by-step explanation:Well we know that for two angles A , B

it holds that cos ( A + B ) = cos A cos B − sin A ⋅ sin B hence for A = B you get cos ( 2 A ) = cos 2 A − sin 2 A But sin 2 A = 1 − cos 2 A


7 0
3 years ago
Read 2 more answers
An article includes the accompanying data on compression strength (lb) for a sample of 12-oz aluminum cans filled with strawberr
Veseljchak [2.6K]

Answer:

<em>The calculated value |t| = 2.375 > 2.1009  at 0.05 level of significance</em>

<em>Null hypothesis is rejected </em>

<em>Alternative hypothesis is accepted</em>

<em>The extra carbonation of cola results in a higher average compression strength</em>

<u><em /></u>

Step-by-step explanation:

<u><em>Step(i):-</em></u>

<em>Given data</em>

<em>First sample size (n₁) = 10 </em>

<em>mean of the first sample(x₁⁻) = 537</em>

<em>standard deviation of the first sample (S₁) = 22</em>

<em>second sample size (n₂) = 10 </em>

<em>mean of the second sample (x₂⁻) = 559</em>

<em>standard deviation of the second sample (S₂) = 17</em>

<u><em>Step(ii)</em></u><em>:-</em>

<u><em>Null hypothesis : H₀:</em></u><em>- The extra carbonation of cola results in a lower average compression strength</em>

<u>Alternative Hypothesis :H₁</u>

<em>The extra carbonation of cola results in a higher average compression strength</em>

<u><em>Step(iii)</em></u><em>:-</em>

<em>By using student's t -test for difference of means</em>

<u><em>Test statistic</em></u>

<em>       </em>t = \frac{x^{-} _{1}-x^{-} _{2}  }{\sqrt{S^{2} (\frac{1}{n_{1} }+\frac{1}{n_{2} }  } )}<em />

<em>  where </em>

<em>     </em>S^{2}  = \frac{n_{1}S^{2} _{1} + n_{2} S_{2} ^{2}  }{n_{1}+n_{2} -2 }<em />

<em>    </em>S^{2}  = \frac{10(22)^{2}  + 10 (17) ^{2}  }{10+10 -2 } = \frac{ 7730}{18} = 429.4<em />

<em>    </em>t = \frac{537-559 }{\sqrt{429.4 (\frac{1}{10 }+\frac{1}{10 }  } )}<em />

<em>   t =  -2.375</em>

<em>|t| = |-2.375| = 2.375</em>

<em>Degrees of freedom</em>

<em>γ = n₁+n₂ -2 = 10+10-2 =18</em>

<em />t_{\frac{\alpha }{2} ,n-1}=t_{(\frac{0.05}{2} ,18)} = t_{(0.025,18)}}=2.1009<em />

<em>The calculated value |t| = 2.375 > 2.1009  at 0.05 level of significance</em>

<em>Null hypothesis is rejected </em>

<em>Alternative hypothesis is accepted</em>

<u><em>Final answer:-</em></u>

<em>The extra carbonation of cola results in a higher average compression strength</em>

<u><em /></u>

<em />

<em> </em>

<em />

5 0
2 years ago
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