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3 years ago

12

Explain how you could calculate the surface area of a square pyramid.

2 answers:

lesya [120]3 years ago

8 0

To find the surface area, use this square pyramid surface area formula: Square Pyramid Surface Area = 2 x B x S + B 2 B = Width of the Square Base S = Slant length of one of the triangular faces and is calculated from the height and base width by using the equation: S= The square root of [(.5B) 2 + Height 2] .

saul85 [17]3 years ago

4 0

Step-by-step explanation

To find the surface area of a pyramid, start by multiplying the perimeter of the pyramid by its slant height. Then, divide that number by 2. Finally, add the number you get to the area of the pyramid's base to find the surface area.

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4 years ago

Select the basic integration formula you can use to find the indefinite integral.

kondaur [170]

Answer:

$\int \dfrac{du}{u}=\log|u|+C$

$\int u^n du=\dfrac{u^{n+1}}{n+1}+C$

$\int \dfrac{du}{u\sqrt{u^2-a^2}}=\dfrac{1}{a}\csc^{-1}(\dfrac{x}{a})+C$

Step-by-step explanation:

a.

$\int \dfrac{du}{u}=\log|u|+C$ $[\because \int \dfrac{dx}{x}=\log |x|+C]$

b.

$\int u^n du=\dfrac{u^{n+1}}{n+1}+C$ $[\because \int x^n dx=\dfrac{x^{n+1}}{n+1}+C]$

c.

$\int \dfrac{du}{u\sqrt{u^2-a^2}}=\dfrac{1}{a}\csc^{-1}(\dfrac{x}{a})+C$ $[\because \dfrac{adx}{x\sqrt{x^2-a^2}}=\csc^{-1}(\dfrac{x}{a})+C]$

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3 years ago

The sides OP and RO of triangle POR are produced to points S and T respectively. If ∠SPR = 145° and ∠POT = 115° , find ∠PRO

Margarita [4]

Answer:

$\angle PRQ = 80$

Step-by-step explanation:

Given

$\angle SPR = 145^o$

$\angle POT = 115^o$

See attachment

Required

Find $\angle PRO$

First, calculate $\angle RPO$

$\angle RPO + \angle SPR = 180$ --- angle on a straight line

So, we have:

$\angle RPO + 145 = 180$

Collect like terms

$\angle RPO = 180 - 145$

$\angle RPO = 35$

Next, calculate PQR

$\angle POR + \angle POT = 180$

So, we have:

$\angle POR + 115 = 180$

Collect like terms

$\angle POR = 180-115$

$\angle POR = 65$

So, PRO is calculated as:

$\angle PRO + \angle POR + \angle RPO = 180$ --- angles in a triangle

So, we have:

$\angle PRO + 65 + 35= 180$

$\angle PRO + 100= 180$

Collect like terms

$\angle PRO = 180-100$

$\angle PRO = 80$

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3 years ago