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soldier1979 [14.2K]
3 years ago
7

The graph shows the cost per day for renting a car. Which statement is true

Mathematics
1 answer:
Angelina_Jolie [31]3 years ago
3 0
Where is the graph and statements?
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Lisa collected leaves from different trees for a sience project. Everyday for a week she collected 7 leaves how many leaves did
julsineya [31]
The total number of leaves that was collected by Lisa is the product of the number of days in a week and the number of leaves she collected per tree. This is shown below,              (7 trees / week) x (7 leaves / 1 tree) = 49 leaves / weekThus, Lisa collected 49 leaves in a week. 

5 0
3 years ago
Help needed
RoseWind [281]
<span>f(x)= x³-x²-9x+9 has x², so it will be many to one function ( one value of y will correspond several values of x).

Answer is B.</span>

6 0
3 years ago
Help me with 16,18 and 20
Mandarinka [93]
16: -7(5)= -35 ( REMEMBER THE MOUTH EATS THE BIGGEST NUMBER!)
     -6(-6)= 36   therefore 36 is greater than -35
18: they are exactly the same because in multiplication with inters it matters when the signs change. so 3(-6) = -18 ad -3(6)= -18 then -18=-18
20: Same as 18 where division has the same rules. if 8x5=40 then 40/8=5
-40/8=-5 and 40/(-8)=-5 then -5=-5
answers: 
8 0
3 years ago
Read 2 more answers
Larissa is measuring fabric to make a homecoming banner. She knows that the fabric is 1 and 1/2 yard wide. If she wants her bann
WINSTONCH [101]
It’s very confusing but just think ab it
8 0
3 years ago
Q5: The probability that event A occurs is 5/7 and the probability that event B occurs is 2/3 . If A and B are independent event
bekas [8.4K]

Answer:

P(A \cap B)

And we can use the following formula:

P(A \cap B)= P(A)* P(B)

And replacing the info we got:

P(A \cap B) = \frac{5}{7} \frac{2}{3}= \frac{10}{21}=0.476

Step-by-step explanation:

We define two events for this case A and B. And we know the probability for each individual event given by the problem:

p(A) = \frac{5}{7}

p(B) = \frac{2}{3}

And we want to find the probability that A and B both occurs if A and B are independent events, who menas the following conditions:

P(A|B) = P(A)

P(B|A) = P(B)

And for this special case we want to find this probability:

P(A \cap B)

And we can use the following formula:

P(A \cap B)= P(A)* P(B)

And replacing the info we got:

P(A \cap B) = \frac{5}{7} \frac{2}{3}= \frac{10}{21}=0.476

7 0
3 years ago
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