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LekaFEV [45]
3 years ago
11

Mrs. Kosko left $19.47 on the table in a restaurant after receiving the bill for $16.50. If there was no tax, what percent did s

he tip? (A) 15% (B) 13% (C) 17% (D) 18%
Mathematics
2 answers:
attashe74 [19]3 years ago
7 0
Take the cost of the bill and add the tip percentage of the bill. That is:

cost = bill + (bill \times\% \: tip)

or

cost = bill(1 + \% \: tip)

solve:

19.47 = 16.50(1 + \% \: tip)

\frac{19.47}{16.50} = 1 + \% \: tip

1.18 = 1 + \% \: tip

\% \: tip = 0.18 = 18\%

The tip was 18% of the bill.
spayn [35]3 years ago
6 0
She tipped 18 percent . 16.50x0.18= 2.97. 16.50+2.97= 19.47
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3) Factor out the common term 4.

-  \frac{4(2x - 1)}{2}  + 3x - 5

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3 years ago
Write the coordinates of the vertices after a reflection across the line y = 2.
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using the same  process:-

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4 years ago
You have two circles, one with radius r and the other with radius R. You wish for the difference in the areas of these two circl
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Answer:

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Step-by-step explanation:

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A=\pi \times (radius)^{2}

For circle with radius 'r' we have

A_{1}=\pi \times (r)^{2}

For circle with radius 'R' we have

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\Rightarrow \pi r^{2}-\pi R^{2}\leq \frac{5}{\pi }\\\\\Rightarrow (r^{2}-R^{2})\leq \frac{5}{\pi ^{2}}\\\\(r+R)(r-R)\leq \frac{5}{\pi ^{2}}\\\\\because (a^{2}-b^{2})=(a+b)(a-b)\\\\(r+R)=10(Given)\\\\\Rightarrow(r-R)\leq \frac{5}{10\pi ^{2}}\\\\\therefore (r-R)\leq\frac{1}{2\pi ^{2}}

Thus maximum difference of radii =(r-R)=\frac{1}{2\pi ^{2}}

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