What are the answers being provided ?
Suppose the larger pump alone can empty the tank in L hours, and the smaller pump can finish the job in S hours, then each hour the large pump empties 1/L portion of the tank, and the small pump empties 1/S per hour
Working together for three hours, they empty the whole tank, which is 100% of it, so 3/L+3/S=100%=1
Larger pump can empty the tank in 4 hours less than the smaller one, so L=S-4
replace L: 3/(S-4)+3/S=1
Make the denominator the same to solve for:
3S/[S(S-4)] +3(S-4)/[S(S-4)]=1
(3S+3S-12)/[S(S-4)]=1
(3S+3S-12)=[S(S-4)]
S^2-10s+12=0
use the quadratic formula to solve for S
S is about 8.6
The answer is not whole hour.
Answer:
Step-by-step explanation:
Answer:
$18
Step-by-step explanation:
1. Subtract 5-2 to get three
2. Divide 27 by three to get 9. Now you know how many $ is in one sectio
3. Multiply 9 by 2
4. Riley got $18
Depends on your question...
If your question is r + 0.12 = 0.20 then do this:
Subtract 0.12 from both sides
r = 0.08
The answer is B.
If your question is r - 0.12 = 0.20 then do this:
Add 0.12 on both sides
r = 0.32
The answer is A
So it depends on your question :P
