the zero of the quadratic polynomial x^2+99x+127 are a both positive b both negative c one +ve one-ve d both equal. please help
2 answers:
Step-by-step explanation:
By Descrates' Rule of Signs,
x² + 99x + 127 changes sign 0 times.
Hence it has 0 positive roots.
Since the discriminant b² - 4ac is also positive, there are 2 real distinct roots.
Hence both the roots are negative. (B)
Answer:
Hi Aarav
Your answer in attached below
LoL
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