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seropon [69]
2 years ago
15

the zero of the quadratic polynomial x^2+99x+127 are a both positive b both negative c one +ve one-ve d both equal. please help​

Mathematics
2 answers:
Paha777 [63]2 years ago
7 0

Step-by-step explanation:

By Descrates' Rule of Signs,

x² + 99x + 127 changes sign 0 times.

Hence it has 0 positive roots.

Since the discriminant b² - 4ac is also positive, there are 2 real distinct roots.

Hence both the roots are negative. (B)

Alenkinab [10]2 years ago
4 0

Answer:

Hi Aarav

Your answer in attached below

LoL

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And E=x1=0, x2 =2 over 3

Alternative form

x1=0, x2=0.666667.

question A

Solving steps:Solve the quadratic equation

x²+6x-16=0

write 6x as a difference

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Solving steps:Number of solution

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