What is the measure of the complement of JKI? the supplement
1 answer:
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Completing the square follows the principle of taking 
and converting it into 
where d is the 'correctional number' as I like to call it - i.e. the number that converts the expanded bracket into the +c, since the expanded bracket will give us 
.
In this case, 2/2=1 so we have the first part:
.
Expanding this gives us
. We need c to be 9, so we can just add 8.
Putting this together:
Now we can solve it more easily.
Rearranging:
In this case, 2/2=1 so we have the first part:
Expanding this gives us
Putting this together:
Now we can solve it more easily.
Rearranging:
So the car is moving at 651 revolutions per minute, with wheels of a radius of 18inches
so, one revolution, is just one go-around a circle, and thus 2π, 651 revolutions is just 2π * 651, or 1302π, the wheels are moving at that "angular velocity"
now, what's the linear velocity, namely, the arc covered per minute
well
now, how much is that in miles/hrs? well
let's keep in mind that, there are 12inches in 1foot, and 5280ft in 1mile, whilst 60mins in 1hr
thus
notice, after all the units cancellations, you're only left with mi/hrs
so, one revolution, is just one go-around a circle, and thus 2π, 651 revolutions is just 2π * 651, or 1302π, the wheels are moving at that "angular velocity"
now, what's the linear velocity, namely, the arc covered per minute
well
now, how much is that in miles/hrs? well
let's keep in mind that, there are 12inches in 1foot, and 5280ft in 1mile, whilst 60mins in 1hr
thus
notice, after all the units cancellations, you're only left with mi/hrs