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Stolb23 [73]
3 years ago
14

What is the measure of the complement of JKI? the supplement

Mathematics
1 answer:
Anna71 [15]3 years ago
4 0

The answer would be 35 and for supplement it would be 125

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V)<br> a common multiple of 6 and 8,<br> What number is a common multiple of 6 and 8?
Vaselesa [24]

Answer:

6, 12, 18, 24, 30, 36, etc.

4 0
3 years ago
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Solve for x (13x + 2) (5x - 7) (3x - 4)<br><br><br> Thank you
Law Incorporation [45]

\huge \bf༆ Answer ༄

As we know, sum of interior angles of a triangle is 180°

that is ~

  • \sf13x + 2 + 5x - 7 + 3x - 4 = 180

  • \sf21x  - 9 = 180

  • \sf21x = 180 + 9

  • \sf x =  \dfrac{189}{21}

  • \sf x = 9 \degree

Hence, value of x is 9°

5 0
3 years ago
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What is the value of (6.6*10¹⁷)-(9.2*10¹⁴) over (4*10¹⁶)
Gennadij [26K]

Answer:

6.59999999999999999977 × 10^17

Step-by-step explanation:

6.6 x 10^17 - (9.2 x 10^14)/(4 x 10^16)

4 0
3 years ago
In order to estimate the difference between the average hourly wages of employees of two branches of a department store, the fol
Julli [10]

Answer:

0.071,1.928

Step-by-step explanation:

                                                Downtown Store   North Mall Store

Sample size   n                             25                        20

Sample mean \bar{x}                         $9                        $8

Sample standard deviation  s       $2                        $1

n_1=25\\n_2=20

\bar{x_1}=9\\ \bar{x_2}=8

s_1=2\\s_2=1

x_1-x_2=9-8=1

Standard error of difference of means = \sqrt{\frac{s_1^2}{n_1}+\frac{s_2^2}{n_2}}

Standard error of difference of means = \sqrt{\frac{2^2}{25}+\frac{1^2}{20}}

Standard error of difference of means = 0.458

Degree of freedom = \frac{\sqrt{(\frac{s_1^2}{n_1}+\frac{s_2^2}{n_2}})^2}{\frac{(\frac{s_1^2}{n_1})^2}{n_1-1}+\frac{(\frac{s_2^2}{n_2})^2}{n_2-1}}

Degree of freedom = \frac{\sqrt{(\frac{2^2}{25}+\frac{1^2}{20}})^2}{\frac{(\frac{2^2}{25})^2}{25-1}+\frac{(\frac{1^2}{20})^2}{20-1}}

Degree of freedom =36

So, z value at 95% confidence interval and 36 degree of freedom = 2.0280

Confidence interval = (x_1-x_2)-z \times SE(x_1-x_2),(x_1-x_2)+z \times SE(x_1-x_2)

Confidence interval = 1-(2.0280)\times 0.458,1+(2.0280)\times 0.458

Confidence interval = 0.071,1.928

Hence Option A is true

Confidence interval is  0.071,1.928

4 0
3 years ago
Use the scatter plot to fill in the missing coordinate of the ordered pair?​
Leona [35]

Answer:

Pairs (0, 14) and (10, 0)

5 0
3 years ago
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