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LuckyWell [14K]
3 years ago
14

Ryan orders a pizza with a 20 inch diameter and asks for a cheese stuff crust along its border . The cheese filled border measur

es blank inches
Mathematics
1 answer:
Kitty [74]3 years ago
5 0
C = pi x d
So the border is about 3.1 x 20 = 62 inches
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Is the ordered pair (4,-3) a solution for the following system of linear inequalities?
Sergio039 [100]

Answer:

no

Step-by-step explanation:

(4, -3) when plugged into the inequality x + y < 1 is not true

4 + (-3) < 1 is not true because 1 is not less than 1

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3 years ago
<img src="https://tex.z-dn.net/?f=3%28%20%7Bx%7D%5E%7B2%7D%20%20%2B%7B3x%7D%5E%7B2%7D%20%20-%202%29" id="TexFormula1" title="3(
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The answer should be 12x^2-6
7 0
3 years ago
Read 2 more answers
Distance between two ships At noon, ship A was 12 nautical miles due north of ship B. Ship A was sailing south at 12 knots (naut
frozen [14]

Answer:

a)\sqrt{144-288t+208t^2} b.) -12knots, 8 knots c) No e)4\sqrt{13}

Step-by-step explanation:

We know that the initial distance between ships A and B was 12 nautical miles. Ship A moves at 12 knots(nautical miles per hour) south. Ship B moves at 8 knots east.

a)

We know that at time t , the ship A has moved 12\dot t (n.m) and ship B has moved 8\dot t (n.m). We also know that the ship A moves closer to the line of the movement of B and that ship B moves further on its line.

Using Pythagorean theorem, we can write the distance s as:

\sqrt{(12-12\dot t)^2 + (8\dot t)^2}\\s=\sqrt{144-288t+144t^2+64t^2}\\s=\sqrt{144-288t+208t^2}

b)

We want to find \frac{ds}{dt} for t=0 and t=1

\sqrt{144-288t+208t^2}|\frac{d}{dt}\\\\\frac{ds}{dt}=\frac{1}{2\sqrt{144-288t+208t^2}}\dot (-288+416t)\\\\\frac{ds}{dt}=\frac{208t-144}{\sqrt{144-288t+208t^2}}\\\\\frac{ds}{dt}(0)=\frac{208\dot 0-144}{\sqrt{144-288\dot 0 + 209\dot 0^2}}=-12knots\\\\\frac{ds}{dt}(1)=\frac{208\dot 1-144}{\sqrt{144-288\dot 1 + 209\dot 1^2}}=8knots

c)

We know that the visibility was 5n.m. We want to see whether the distance s was under 5 miles at any point.

Ships have seen each other = s\leq 5\\\\\sqrt{144-288t+208t^2}\leq 5\\\\144-288t+208t^2\leq 25\\\\199-288t+208t^2\leq 0

Since function f(x)=199-288x+208x^2 is quadratic, concave up and has no real roots, we know that 199-288x+208x^2>0 for every t. So, the ships haven't seen each other.

d)

Attachedis the graph of s(red) and ds/dt(blue). We can see that our results from parts b and c were correct.

e)

Function ds/dt has a horizontal asympote in the first quadrant if

                                                \lim_{t \to \infty} \frac{ds}{dt}

So, lets check this limit:

\lim_{t \to \infty} \frac{ds}{dt}=\lim_{t \to \infty} \frac{208t-144}{\sqrt{144-288t+208t^2}}\\\\=\lim_{t \to \infty} \frac{208-\frac{144}{t}}{\sqrt{\frac{144}{t^2}-\frac{288}{t}+208}}\\\\=\frac{208-0}{\sqrt{0-0+208}}\\\\=\frac{208}{\sqrt{208}}\\\\=4\sqrt{13}

Notice that:

4\sqrt{13}=\sqrt{12^2+5^2}=√(speed of ship A² + speed of ship B²)

5 0
3 years ago
Please help me please
MissTica

Answer:

not all of them are proportional because they do not all equal the same.

Step-by-step explanation:

6 0
2 years ago
Read 2 more answers
Is <img src="https://tex.z-dn.net/?f=1-2x%5E%7B2%7D" id="TexFormula1" title="1-2x^{2}" alt="1-2x^{2}" align="absmiddle" class="l
Schach [20]

Answer:

standard form for a quadratic expression

Step-by-step explanation:

This is a quadratic expression.  If you want this expression in standard form, write the terms in descending order of powers of x:  -2x^2 + 1.

This   -2x^2 + 1   has not yet been factored.

-2x^2 + 1 is in standard form.

7 0
2 years ago
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