Answer:
x= -1/3
x = -7
Step-by-step explanation:
9x^2 +66x+21 = 0
a=9 b=66 c=21
quadratic formula
x=(-b +/- square root of (b^2 – 4ac))/(2a)
x = (-66 +/- square root of (66^2 -4*9*21))/(2*9)
x = (-66 +/- square root of (4356 -756))/(18)
x = (-66 +/- square root of (3600))/(18)
x = (-66 +/- 60)/18
split the fraction
(-66 +/- 60)/18 = -6/18 and -126/18 because of the +/-
x = -6/18 x = -126/18
x = -1/3 x = -7
Answer:
70% (Sorry, had to use the word "com" instead...)
Step-by-step explanation:
The question is asking what percent of students who graduated one of these three schools, graduated from either com laude or magna com laude. You need a total of how many students graduated com laude and how many from magna com laude. 4 graduated from magna com laude, and 10 graduated from com laude. That's 14. Now we need a total of how many students graduated in total. 14 graduated from com laude or magna com laude, and 6 graduated from summa com laude for a total of 20 who graduated. So you just need to do 14 divided by 20, and you'll get the decimal from which you can get a percent. 14 divided by 20 is 0.7. So, that's 70%. 70% of students who graduated, graduated from Magna com laude or Com laude.
Here is a step by step tutorial!
All you do is multiply 24 and 16 by 1/4
6 - 4x
