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drek231 [11]
3 years ago
6

G(n)=n2-5n; find g(-8)

Mathematics
2 answers:
azamat3 years ago
4 0
G(-8)=(-8)^2-5(-8)
=64+40
g(-8)=104
Hatshy [7]3 years ago
4 0

Answer:

G(-8) = 104

Step-by-step explanation:

G(n) = n^2- 5n.....find G(-8)

what ur basically doing is subbing in -8 for n

G(-8) = (-8)^2 - 5(-8)

G(-8) = 64 + 40

G(-8) = 104 <====

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For the function defined by I = 50/t, what can you say about the relationship between the variables I and t?
sveticcg [70]

Answer:

Inverse proportionality relationship

Step-by-step explanation:

SInce I equals 50 divided by t, we see "t in the denominator, which corresponds to an INVERSE proportionality between these variables (I and t)

8 0
3 years ago
Which of these points lies on the circle with the center (2,3) and radius 2?
yan [13]

Answer:

The answer to your question is the letter A.

Step-by-step explanation:

Data

Center = (2, 3)

radius = 2

Process

1.- Find the equation of the line

              (x - h)² + (y - k)² = r²

-Substitution

              (x - 2)² + (y - 3)² = 2²  

-Simplification

              (x - 2)² + (y - 3)² = 4

-Evaluate the points in the equation

A. (4, 3)

              (4 - 2)² + (3 - 3)² = 4

                   2² + 0 = 4

                           4 = 4     This point lies in the circle

B (-1, 0)

              (-1 - 2)² + (0 - 3)² = 4

                        -3² + (-3)² = 4

                          9 + 9 = 4   This point is not part of the circle

C. (1, 3)

              (1 - 2)² + (3 - 3)² = 4

                 (-1)² + (0)² = 4

                            1 = 4          This point is not part of the circle

D. (3, 4)

              (3 - 2)² + (4 - 3)² = 4

                     1² + 1² = 4

                            2 = 4          This point is not part of the circle

5 0
3 years ago
Read 2 more answers
Can some please help me?
PilotLPTM [1.2K]

Answer:

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8 0
1 year ago
Read 2 more answers
SOMEONE HELP ME WITH THIS ONE PLZ!
kolezko [41]
To construct a circle that circumscribes to a triangle, you would have to construct a circle that where all vertices of the triangle are on the circle. To do this you would have to construct the perpendicular bisectors of each side with your compass and straight edge. Comment on this answer if you are unsure of how to construct a perpendicular bisect (it's a long fundamental process to describe, and I wouldn't want to lecture you one something you already know). Once you have done so, set your compass point on the point where all perpendicular bisectors intersect (they should intersect in ONE point, if not you will have to redo it). Set your other compass lead on one of the vertices and spin away! If you have done this correctly, you should hit all three vertices when spinning your compass. Hope this helps!

Fun fact: the point where all perpendicular bisectors intersect is called the circumcenter
3 0
3 years ago
HELP ME MATH ILL GIVE YOU BRAINLIEST
s344n2d4d5 [400]

Answer:

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Step-by-step explanation:

I like to use a graphing calculator for finding the zeros of higher order polynomials. The attachment shows them to be at x = -3, -1, +2.

__

The zeros can also be found by trial and error, trying the choices offered by the rational root theorem: ±1, ±2, ±3, ±6. It is easiest to try ±1. Doing so shows that -1 is a root, and the residual quadratic is ...

  x² +x -6

which factors as (x -2)(x +3), so telling you the remaining roots are -3 and +2.

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For any odd-degree polynomial with a positive leading coefficient, the sign of the function will match the sign of x when the magnitude of x gets large. Thus as x approaches negative infinity, so does f(x).

8 0
3 years ago
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