Answer:
32
Step-by-step explanation:
77 quarters and dimes
q + d = 77
subtract q from both sides
d = 77 - q
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A collection of quarters and dimes is worth $12.50 (1250 cents)
25q + 10d = 1250
substitute for d
25q + 10(77 - q) = 1250
distribute
25q + 770 - 10q = 1250
Combine like terms
15q + 770 = 1250
subtract 770 from both sides
15q = 480
divide both sides by 15
q = 32
Part (1):
8/z = 10/25 = 6/15
This can be simplified as:
8/z = 2/5
Use cross multiplication as follows:
8*5 = 2*z
40 = 2z
z = 40/2 = 20
Part (2):
<span>12/36 = 14/42 = 8/t
This can be simplified into:
8/t = 1/3
Use cross multiplication as follows:
3*8 = t*1
t = 24</span>
Answer:
C) 
Step-by-step explanation:
Given Equations:
A) 
B) 
In order to eliminate 
we need to multiply 
to equation B and add it to A.
Multiplying to B.
⇒ 
⇒ 
⇒ 
Adding it equation A.
+ 
We get 
Thus is eliminated.
So, the expression used to eliminate is:
So our integer <span> and the consecutive integer</span><span /><span> </span><span>.</span><span /><span> The smaller integer is 90.</span>
