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2 years ago

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A collection of 77 quarters and dimes is worth $12.50. How many quarters are in the collection? PLS HELP ILL GIVE YOU BRAINLEST

ANSWER

1 answer:

mrs_skeptik [129]2 years ago

3 0

Answer:

32

Step-by-step explanation:

77 quarters and dimes

q + d = 77

subtract q from both sides

d = 77 - q

---------------------------

A collection of quarters and dimes is worth $12.50 (1250 cents)

25q + 10d = 1250

substitute for d

25q + 10(77 - q) = 1250

distribute

25q + 770 - 10q = 1250

Combine like terms

15q + 770 = 1250

subtract 770 from both sides

15q = 480

divide both sides by 15

q = 32

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Area of regular polygons

Finger [1]

Hello!

To find the area of a hexagon you do 3 $\frac{3 \sqrt{3} }{2} } a^{2}$ where a is one of the sides

Since the perimeter is 60 we can do 60/ the sides of the shape

60/6 = 10

So one side is equal to 10

you put that into the formula to get the area of a hexagon and you get 259.81

Hope this helps!

8 0

2 years ago

Find all the zeros for each function P(x)=x^4-4x^3-x^2+20x-20

ivanzaharov [21]

Answer:

The zeros of the given polynomial function are

2,2, $\pm\sqrt{5}$

Step-by-step explanation:

Given polynomial is $P(x)=x^4-4x^3-x^2+20x-20$

To find the zeros equate the given polynomial to zero

ie., P(x)=0

$P(x)=x^4-4x^3-x^2+20x-20=0$

By using synthetic division we can solve the polynomial:

2_| 1 -4 -1 20 -20

0 2 -4 -10 20

_____________________

1 -2 -5 10 |_0

Therefore x-2=0

x=2 is a zero of P(x)

Now we can write the cubic equation as below:

$x^3-2x^2-5x+10=0$

Again using synthetic division

2_| 1 -2 -5 10

0 2 0 -10

______________

1 0 -5 |_0

Therefore x-2=0

x=2 is also a zero of P(x).

Now we have $x^2+0x-5=0$

$x^2-5=0$

$x^2=5$

$x^=\pm\sqrt{5}$ is a zero of P(x)

Therefore the zeros are 2,2, $\pm\sqrt{5}$

8 0

3 years ago

Camellia earned $160 over the summer. If you put 80% of earnings into her savings account and spent 75% of the rest on a gift fo

In-s [12.5K]

Answer: She has left over $8.

Step-by-step explanation:

Hi, to answer this question we have to analyze the information given:

<em>Camellia earned $160 and you put 80% of earnings into her savings account: </em>

So, to obtain this number we have to multiply Camellia's earnings by 0.80 (the percentage in decimal form, 80 /100 = 0.80)

$160 x 0.80 = $128 (savings)

If we subtract the number obtained to Camellia's earnings:

$160 -$128 = $32 (money left without purchasing a gift)

<em>She spent 75% of the rest on a gift for her </em>

The rest is $32, so we have to multiply it by the percentage in decimal form (75/100=0.75)

$32 x 0.75 (decimal form) = $24

And finally, subtract that number to the original rest.

$32-$24 = $8

She has left over $8.

7 0

2 years ago

Read 2 more answers

PLEASE HELP!!! Thanks in advance!! Henry is a ringmaster for the circus. He stands inside a circular circus ring that has a circ

Andreas93 [3]

Circumference = 2pi * r

So

3pi = 2pi r divide away pi

3 = 2 r

(3/2) = r = 1.5 m

Area = pi ( r^2) = pi (1.5)^2 = 2.25 pi m^2 ≈ 7.07 m^2

cited from web2.0calc

3 0

2 years ago

Hey could someone please help me with this really hard assignment is taking me forever. Thank you marking brainliest!

rewona [7]

Answer:

Exercise 1: The length of the unknown leg is 4 inches.

Exercise 3: The following straws can be used to construct the triangle: b) $3\,in$ , c) $4.5\,in$ , d) $6.5\,in$ , e) $10\,in$ , f) $13.5\,in$

Exercise 4: Possible options of this exercise: 1) (2, 4, 5), 2) (4, 5, 6), 3) (5, 6, 10), 4) (1, 2, 11), 5) (1, 4, 11), 6) (1, 10, 11)

Step-by-step explanation:

Exercise 1:

Let suppose that triangle represented in the figure is a right triangle, the length of the missing leg is determined by Pythagorean Theorem:

$y = \sqrt{l^{2}-x^{2}}$ (1)

Where:

$l$ - Hypotenuse, in inches.

$x$ - Known leg, in inches.

$y$ - Unknown leg, in inches.

If we know that $l = 11\,in$ and $x = 10\,in$ , then the length of the unknown leg is:

$y = \sqrt{21}$

Since 4 is the least whole number closest to $\sqrt{21}$ , then we conclude that the length of the unknown leg is 4 inches.

Exercise 3:

The range of possible lengths for the missing side of the triangle is represented by the following simultaneous inequality:

$x + y > l > x-y$ (2)

Where:

$x$ - Greater side, in inches.

$y$ - Lesser side, in inches.

$l$ - Missing side, in inches.

If we know that $x = 8\,in$ and $y = 6\,in$ , then we have the following range of missing sides:

$14\,in > l > 2\,in$

The following straws can be used to construct the triangle: b) $3\,in$ , c) $4.5\,in$ , d) $6.5\,in$ , e) $10\,in$ , f) $13.5\,in$

Exercise 4:

Let check each pair to determine possible constructions by means of the inequality used in Exercise 3:

(i) $x = 4\,in, y = 2\,in$

$6\,in>l>2\,in$

Possible choices: 5 inches.

(ii) $x = 5\,in, y = 2\,in$

$7\,in > l > 3\,in$

Possible choices: 4 inches, 6 inches.

(iii) $x = 6\,in, y = 2\,in$

$8\,in > l > 4\,in$

Possible choices: 5 inches, 6 inches.

(iv) $x = 10\,in, y = 2\,in$

$12\,in > l > 8\,in$

Possible choices: None.

(v) $x = 5\,in, y = 4\,in$

$9\,in > l > 1\,in$

Possible choices: 2 inches, 6 inches.

(vi) $x = 6\,in, y = 4\,in$

$10\,in > l > 2\,in$

Possible choices: 5 inches.

(vii) $x = 10\,in, y = 4\,in$

$14\,in > l > 6\,in$

Possible choices: None.

(viii) $x = 6\,in, y = 5\,in$

$11\,in > l > 1\,in$

Possible choices: 2 inches, 4 inches, 10 inches.

(ix) $x = 10\,in, y = 5\,in$

$15\,in > l > 5\,in$

Possible choices: 6 inches.

(x) $x = 10\,in, y = 6\,in$

$16\,in > l > 4\,in$

Possible choices: 5 inches.

Possible options of this exercise: 1) (2, 4, 5), 2) (4, 5, 6), 3) (5, 6, 10), 4) (1, 2, 11), 5) (1, 4, 11), 6) (1, 10, 11)

7 0

2 years ago

Read 2 more answers