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Iteru [2.4K]
3 years ago
15

Find the greatest common factor of 8 a3b2 and 12 ab4 .

Mathematics
2 answers:
Kruka [31]3 years ago
8 0
4ab^2
Hoped this helps! Just had it on a quiz and got it right. If you have boxex by 4 a^1 b^2
neonofarm [45]3 years ago
6 0

Answer:

The greatest common factor = 4a.b^2

Step-by-step explanation:

Given: 8a^3.b^2 and 12ab^4

To find the greatest common factor, we have to find the prime factors.

8 a^3.b^3 = 2.2.2.a.a.a.b.b

12a.b^4 = 2.2.3.a.b.b.b.b

The greatest common factor = 2.2.a.b.b

The greatest common factor = 4a.b^2

Hope this will helpful.

Thank you.

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Answer:

3. B

Step-by-step explanation:

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Answer is B.

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3 years ago
A gym charges an initial fee plus $25 per month. John paid $200 for six months. Assume the relationship is linear.
charle [14.2K]

Step-by-step explanation:

a. The rate of change is $33.33 per month

200/6 = approximately $33.33 per month

This means that in addition to the initial fee, Josh has to pay $33.33 per month for the gym membership.

b. The initial value is $25. This is a constant value and a one time fee to open and attain a gym membership.

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In the 500 spin test, 4 was chosen 121 times.  This mean it was chosen 121 times out of 500, or 121/500.

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4 0
4 years ago
Read 2 more answers
In a rectangle FGHI, diagonals FH and GI intersect at E<br> What is the length of FH?
Hunter-Best [27]

Answer:

The length of \overline {FH} is;

D. 38 units

Step-by-step explanation:

The given parameters are;

The type of the given quadrilateral FGHI = Rectangle

The diagonals of the quadrilateral = \overline {FH} and \overline {GI}

The length of IE = 3·x + 4

The length of EG = 5·x - 6

We have from segment addition postulate, \overline {GI} = IE + EG

The properties of a rectangle includes;

1) Each diagonal bisects the other diagonal into two

Therefore,  \overline {FH} bisects \overline {GI}, into two equal parts, from which we have;

IE = EG

\overline {GI} = IE + EG

3·x + 4 = 5·x - 6

4 + 6 = 5·x - 3·x = 2·x

10 = 2·x

∴ x = 10/2 = 5

From which we have;

IE = 3·x + 4 = 3 × 5 + 4 = 19 units

EG = 5·x - 6 = 5 × 5 - 6 = 19 units

\overline {GI} = IE + EG = 19 + 19 = 38 units

\overline {GI} = 38 units

2) The lengths of the two diagonals are equal. Therefore, the length of segment \overline {FH} is equal to the length of segment \overline {GI}

Mathematically, we have;

\overline {FH} = \overline {GI} = 38 units

∴ \overline {FH} = 38 units.

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3 years ago
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B is the answer. To that question your welcome
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