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Reika [66]
3 years ago
8

A compression scheme for long strings of bits called run-length encoding is described as follows: Rather than record each 0 and

1 individually, instead record "runs" of bits by storing the number of consecutive 1s and 0s that appear. Since it's binary, any run of 0s must be followed by a run of 1s (even if the run is only 1-bit long) and vice versa. Thus, you can store a list of small numbers that represents the alternating runs of 0s and 1s. Here is an example: To uncompress the data back into its original binary state, you simply reverse the process. This technique is an example of what type of compression?
(a) Lossy compression
(b) Lossless compression
(c)Fast Fourier Transform compression
(d)Tailored compression
Computers and Technology
1 answer:
Musya8 [376]3 years ago
3 0

Answer: (B) Lossless compression

Explanation:

 According to the question, the given technique is the example of the lossless compression. The lossless compression is one of the technique that decompress the data into the original data form without any type of losses.

The lossless compression is the technique that usually compress the data, text and the databases. This technique also improve the compression rate helps in reconstruct the original data. It is used in various types of encoding methods, GNU tool and zip file.

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Consider a company that needs to sort an array of structures of type Customer by balance, with the largest balance first. Here i
8090 [49]

Answer:

#include <iostream>

#include <string>

#include <cstring>

#include <cstdlib>

using namespace std;

struct Person

{

string name;

int age;

};

int main()

{

struct Person data[10];

struct Person *pData[10],*temp;

string names[] = {"a","b","c","g","z","l","p","q","r","w"};

int num[] = {4,6,34,8,13,90,33,22,18,23};

for(int i=0;i<9;i++)

{

data[i].name = names[i];

data[i].age = num[i];

pData[i] = &data[i];

}

for(int i=0;i<9;i++)

{

for(int j=i+1;j<9;j++)

{

if(pData[i]->name.compare(pData[j]->name)>0)

{

temp = pData[i];

pData[i] = pData[j];

pData[j] = temp;

}

}

}

for(int i=0;i<9;i++)

{

cout<<pData[i]->name<<" "<<pData[i]->age<<endl;

}

}

Explanation:

The line #include <iostream> initializes the program.

This program created an array of only 10 structures, Customer data. Also defined an auxiliary array Customer *pData.

The program uses these parameters to sorts the array of pointers so that when you go through pData in increasing order of index k, the entries pData[k] point to Customer objects in decreasing order by balance, meaning that pdata[0] now points to the customer with the highest balance, and pData[9] points to the customer with the smallest balance.

4 0
3 years ago
There have not been any changes to instruments or music in the last 50 years. The technology in music is still the same.
aliya0001 [1]

Answer:

False i hope this is rigth

7 0
3 years ago
Write a class called SimpleSquare that has the following properties: - public int field called num - private int field called sq
mezya [45]

Answer:

public class SimpleSquare{

   public int num;

   private int square;

   

   public SimpleSquare(int number){

       num = number;

       square = number * number;

   }

   

   public int getSquare(){

       return square;

   }    

}

Explanation:

*The code is in Java.

Create a class called SimpleSquare

Declare two fields, num and square

Create a constructor that takes an integer number as a parameter, sets the num and sets the square as number * number.

Since the square is a private field, I also added the getSquare() method which returns the value of the square.

6 0
3 years ago
which network component connects a device to transmission media and allows the device to send and receive messages?
krok68 [10]

Answer: Hello!

Network Interface Card (NIC)

Explanation:

Mark me brainest please. Hope I helped! Hope you make an 100%

-Anna♥

5 0
3 years ago
Why is a personal laptop computer NOT a server?
bixtya [17]
I believe the answer is C) <span>servers are used directly by computers, not by people

Have a good day! =)</span>
4 0
3 years ago
Read 2 more answers
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