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marusya05 [52]
3 years ago
14

In microsoft word, when you highlight existing text you want to replace, you’re in

Computers and Technology
1 answer:
Sergio039 [100]3 years ago
6 0
 Hello <span>Christinamauffp2olwu</span><span>

Answer: In Microsoft Word, when you highlight existing text you want to replace, you're in insert mode.

Hope This Helps :-)
-Chris</span>
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Write the name of the tab, the command group, and the icon that you need to use to justify text
const2013 [10]

Answer and Explanation:

In order to use the justified text

The name of the tab is the Home tab

The command is

First select the data in which you want to justify

Than go to the home tab after that go to the paragraph tab and then click on the dialog box launcher after that choose the drop-down menu of alignment and set justified text

The shortcut key is to use it is Ctrl + J

4 0
3 years ago
5)What are the differences in the function calls between the four member functions of the Shape class below?void Shape::member(S
Stells [14]

Answer:

void Shape :: member ( Shape s1, Shape s2 ) ; // pass by value

void Shape :: member ( Shape *s1, Shape *s2 ) ; // pass by pointer

void Shape :: member ( Shape& s1, Shape& s2 ) const ; // pass by reference

void Shape :: member ( const Shape& s1, const Shape& s2 ) ; // pass by const reference

void Shape :: member ( const Shape& s1, const Shape& s2 ) const ; // plus the function is const

Explanation:

void Shape :: member ( Shape s1, Shape s2 ) ; // pass by value

The s1 and s2 objects are passed by value as there is no * or & sign with them. If any change is made to s1 or s2 object, there will not be any change to the original object.

void Shape :: member ( Shape *s1, Shape *s2 ) ; // pass by pointer

The s1 and s2 objects are passed by pointer as there is a * sign and not & sign with them. If any change is made to s1 or s2 object, there will be a change to the original object.

void Shape :: member ( Shape& s1, Shape& s2 ) const ; // pass by reference

The s1 and s2 objects are passed by reference  as there is a & sign and not * sign with them. If any change is made to s1 or s2 object.

void Shape :: member ( const Shape& s1, const Shape& s2 ) ; // pass by const reference

The s1 and s2 objects are passed by reference  as there is a & sign and not * sign with them. The major change is the usage of const keyword here. Const keyword restricts us so we cannot make any change to s1 or s2 object.

void Shape :: member ( const Shape& s1, const Shape& s2 ) const ; // plus the function is const

The s1 and s2 objects are passed by reference  as there is a & sign and not * sign with them. const keyword restricts us so we cannot make any change to s1 or s2 object as well as the Shape function itself.

5 0
3 years ago
In the Budget Details sheet, if you wish to autofill with the formula, you must use a ______ reference for the LY Spend Total ce
ahrayia [7]

Answer:

The answer is A.Absolute reference.

Explanation:

Absolute reference is a cell reference whose location remains constant when the formula is copied.

8 0
3 years ago
You are given an unsorted array x of elements that implement the Comparable interface. There are no duplicates in this array. Yo
Andrei [34K]

Answer:

boolean isEven = false;

if (x.length % 2 == 0)

isEven = true;

Comparable currentMax;

int currentMaxIndex;

for (int i = x.length - 1; i >= 1; i--)

{

currentMax = x[i];

currentMaxIndex = i;

for (int j = i - 1; j >= 0; j--)

{

if (((Comparable)currentMax).compareTo(x[j]) < 0)

{

currentMax = x[j];

currentMaxIndex = j;

}

}

x[currentMaxIndex] = x[i];

x[i] = currentMax;

}

Comparable a = null;

Comparable b = null;

if (isEven == true)

{

a = x[x.length/2];

b = x[(x.length/2) - 1];

if ((a).compareTo(b) > 0)

m = a;

else

m = b;

}

else

m = x[x.length/2];

8 0
3 years ago
Calculate the wait time and turnaround time for FCFS, shortest remaining time, and round-robin by drawing a diagram or chart. As
lidiya [134]

Answer:

id id d

Explanation:

4 0
2 years ago
Read 2 more answers
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