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Vlad [161]
3 years ago
15

If a pond has a major axis of 68 feet and a minor axis of 32 feet how far apart are the foci

Mathematics
1 answer:
Bogdan [553]3 years ago
6 0

Answer:

The distance between foci is 60 feet

Step-by-step explanation:

we are given

a pond has a major axis of 68 feet

so, a=\frac{68}{2} =34

a minor axis of 32 feet

so, b=\frac{32}{2} =16

now, we know ellipse formula

c^2=a^2-b^2

where

c is the distance between center and focus

so, we can plug it and find c

c^2=34^2-16^2

c=30

Distance between foci is

=2c

=2\times 30

=60


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3 0
3 years ago
Please help will mark brainliest
beks73 [17]

Answer:

m\angle N=57^{\circ}

Step-by-step explanation:

From the isosceles-base theorem, the measure of the angles adjacent to the pair of congruent sides of the triangle are equal. Since the problem declares LM\cong LN, the remaining unknown angles are equal (m\angle N=m\angle M). The sum of the interior angles of a triangle always add up to 180^{\circ}$.

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7 0
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