Question

If a pond has a major axis of 68 feet and a minor axis of 32 feet how far apart are the foci

Answer 1

Answer:

The distance between foci is 60 feet

Step-by-step explanation:

we are given

a pond has a major axis of 68 feet

so, $a=\frac{68}{2} =34$

a minor axis of 32 feet

so, $b=\frac{32}{2} =16$

now, we know ellipse formula

$c^2=a^2-b^2$

where

c is the distance between center and focus

so, we can plug it and find c

$c^2=34^2-16^2$

$c=30$

Distance between foci is

$=2c$

$=2\times 30$

$=60$