The alue of 5 is the tenths place.
Answer:
approx 7.81 Exactly: √61
Step-by-step explanation:
Use Pythag theorem: 5^2 + 6^2 = hyp^2 (line AS)
25 + 36 = 61
hyp = √61 or about 7.81
Completing the square follows the principle of taking
![a x^{2} +bx+c](https://tex.z-dn.net/?f=a%20x%5E%7B2%7D%20%2Bbx%2Bc)
and converting it into
![(x+ \frac{b}{2})^2+d](https://tex.z-dn.net/?f=%28x%2B%20%5Cfrac%7Bb%7D%7B2%7D%29%5E2%2Bd%20)
where d is the 'correctional number' as I like to call it - i.e. the number that converts the expanded bracket into the +c, since the expanded bracket will give us
![a x^{2} +b](https://tex.z-dn.net/?f=a%20x%5E%7B2%7D%20%2Bb)
.
In this case, 2/2=1 so we have the first part:
![(w+1)^2](https://tex.z-dn.net/?f=%28w%2B1%29%5E2)
.
Expanding this gives us
![w^2+2w+1](https://tex.z-dn.net/?f=w%5E2%2B2w%2B1)
. We need c to be 9, so we can just add 8.
Putting this together:
![w^2+2w+9=(w+1)^2+8](https://tex.z-dn.net/?f=w%5E2%2B2w%2B9%3D%28w%2B1%29%5E2%2B8)
Now we can solve it more easily.
Rearranging:
Answer:
squares in Step n. f (n) = 8 + 3(n – 1} for n > 1 /(1) = 8, /{n2) = 3+f (n – 1) for n > 2 01)= 8, 7 (n) = 8= ƒ(n=1) forn> 2 Df1)= 3 -8 (n- 1) forn > 1 Of (n) - 37 + 5 for n > 1 32+5 for n>1 CS (n) 3+ an forn 1
Step-by-step explanation:
Answer:
4 units
Step-by-step explanation:
Let ABC be isosceles right angled ∆ right angled at B
By Pythagoras theorem,
AC² = AB² + BC²
(√32)² = 4² + s²
32 = 16 + s²
s² = 32 - 16
s² = 16
s = √16
s = 4 units.
Therefore s = 4 units
Hope it helps...