What are two ratios that are equivelent to 8:5
2 answers:
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Answer:
or
Step-by-step explanation:
Given
Required
Find a, b and c
Median is calculated as:
This means that the median is the average of the 13th and 14th item.
Since the median is (average of 3 and 4),
and:
This implies that c begins at 14
So, the number of houses bedrooms 4 and 5 is:
Also
---- sum of total frequency
Substitute
Since a, b and c are different, then
a and b cannot be 5 because
a and b cannot be 3 because
because b ends at 13
a
So, possible sets are:
Include c, we have:
or
Answer:
B
Step-by-step explanation:
+ 6 = x ( subtract 6 from both sides )
= x - 6 ( square both sides )
x = (x - 6)² ← expand using FOIL
x = x² - 12x + 36 ( subtract x from both sides )
0 = x² - 13x + 36 , that is
x² - 13x + 36 = 0 ← in standard form
(x - 4)(x - 9) = 0 ← in factored form
Equate each factor to zero and solve for x
x - 4 = 0 ⇒ x = 4
x - 9 = 0 ⇒ x = 9
As a check
Substitute these values into the equation and if both sides are equal then they are the solutions.
x = 4
left side = + 6 = 2 + 6 = 8
right side = x = 4
Since 8 ≠ 4 then x = 4 is an extraneous solution
x = 9
left side = + 6 = 3 + 6 = 9
right side = x = 9
Thus the solution is x = 9 → B