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natima [27]
2 years ago
8

Help! what is the missing length?

Mathematics
2 answers:
Softa [21]2 years ago
8 0
Yeah I believe it’s 60 ^^^^^
matrenka [14]2 years ago
3 0

Answer:

Hello! answer: 30

Step-by-step explanation:

32 × 30 = 960 HOPE THAT HELPS!

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Gabriellas school is selling tickets to a fall musical. On the dirst day of ticket sales the school sold 10 senior citizen ticke
Tanya [424]
A senior ticket costs $10, while a student ticket costs $8. You can solve this system of equations by the elimination method.

We can use x as the variable for the senior tickets, and y as the variable for the student tickets and represent it with these equations:
10x+12y=212 and 12x+14y=232

Next, multiply each entire equation by a variable so they can eliminate each other. I used 12 and -10 here so it would be 120x-120x to eliminate that variable.
12(10x+14y=212) and -10(12x+14y=232)

Our new equations are:
(120x +168y= 2544) and (-120x-140y=-2320)

You can then subtract one of the equations from the other leaving you with 28y=224 and solve it for y to get 8.
So the price of a student ticket is 8.

Pick any of the original equations and by replacing y with 8, you can solve to find x. (X is the variable we assigned for senior tickets)
10x+14(8)=212
10x+112=212
10x=212-112
10x= 100
1x=10
6 0
3 years ago
Orange M&M’s: The M&M’s web site says that 20% of milk chocolate M&M’s are orange. Let’s assume this is true and set
SOVA2 [1]

Answer:

The correct option is (A).

Step-by-step explanation:

Let <em>X</em> = number of orange  milk chocolate M&M’s.

The proportion of orange milk chocolate M&M’s is, <em>p</em> = 0.20.

The number of candies in a small bag of milk chocolate M&M’s is, <em>n</em> = 55.

The event of an milk chocolate M&M being orange is independent of the other candies.

The random variable <em>X</em> follows a Binomial distribution with parameter <em>n</em> = 55 and <em>p</em> = 0.20.

The expected value of a Binomial random variable is:

E(X)=np

Compute the expected number of orange  milk chocolate M&M’s in a bag of 55 candies as follows:

E(X)=np

         =55\times 0.20\\=11

It is provided that in a randomly selected bag of milk chocolate M&M's there were 14 orange ones, i.e. the proportion of orange milk chocolate M&M's in a random bag was 25.5%.

This proportion is not surprising.

This is because the average number of orange milk chocolate M&M’s in a bag of 55 candies is expected to be 11. So, if a bag has 14 orange milk chocolate M&M’s it is not unusual at all.

All unusual events have a very low probability, i.e. less than 0.05.

Compute the probability of P (X ≥ 14) as follows:

P(X\geq 14)=\sum\limits^{55}_{x=14}{{55\choose x}0.20^{x}(1-0.20)^{55-x}}

                 =0.1968

The probability of having 14 or more orange candies in a bag of milk chocolate M&M’s is 0.1968.

This probability is quite larger than 0.05.

Thus, the correct option is (A).

4 0
3 years ago
What is the surface area of the rectangle pyramid below?​
iren [92.7K]

Answer:

Um.. where's the picture?... wheres the rectangle and the measurements.

7 0
3 years ago
Can anyone solve this?
anygoal [31]

Answer:

50.4 km (Answer B)

Step-by-step explanation:

From this information, we are able to create a proportion, 2cm/21km= 4.8cm/x km (x representing the actual distance). After cross-multiplying and simplifying, you get an answer of 50.4km. Hope this helps!

6 0
2 years ago
Read 2 more answers
A bench is 35 inches long and 19 inches wide. how many square inches does it cover?
vfiekz [6]
Do 35 times 19 and that is the whole square inches or so 35 squared times 19 squared 
4 0
3 years ago
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