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4 years ago

PLEASE ANSWERRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRR

Mathematics

1 answer:

Lemur [1.5K]4 years ago

4 0

Answer:

2 miles per practice

Step-by-step explanation:

Slope= change in y/change in x

= (50-30)/(10-0)

= 20/10

= 2

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last year Patrick paid £2534 for his annual train ticket this year he has to pay £2612 for his annual train ticket. work out the

Aleonysh [2.5K]

Answer:

Percentage increase in the cost of his train ticket = 3% (Approx.)

Step-by-step explanation:

Given:

Cost of annual ticket paid by Patrick last year = £2,534

Cost of annual ticket paid by Patrick current year = £2,612

Find:

Percentage increase in the cost of his train ticket

Computation:

Percentage increase = [(Current - Base) / Base]100

Percentage increase in the cost of his train ticket = [(2,612 - 2,534) / 2,534]100

Percentage increase in the cost of his train ticket = [(78) / 2,534]100

Percentage increase in the cost of his train ticket = [0.03078]100

Percentage increase in the cost of his train ticket = 3.078

Percentage increase in the cost of his train ticket = 3% (Approx.)

3 0

3 years ago

Which of the following inequalities is correct?

Elina [12.6K]

Answer:

The last one

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Can someone solve this for me?

Sav [38]

Answer:

Step-by-step explanation:

9 is 3/4*12.

3 0

3 years ago

Evaluate the surface integral S F · dS for the given vector field F and the oriented surface S.

sweet-ann [11.9K]

Answer:

2.794

Step-by-step explanation:

Recall that if G(x,y) is a parametrization of the surface S and F and G are smooth enough then

$\bf \displaystyle\iint_{S}FdS=\displaystyle\iint_{R}F(G(x,y))\cdot(\displaystyle\frac{\partial G}{\partial x}\times\displaystyle\frac{\partial G}{\partial y})dxdy$

F can be written as

F(x,y,z) = (xy, yz, zx)

and S has a straightforward parametrization as

$\bf G(x,y) = (x, y, 3-x^2-y^2)$

with 0≤ x≤1 and 0≤ y≤1

$\bf \displaystyle\frac{\partial G}{\partial x}= (1,0,-2x)\\\\\displaystyle\frac{\partial G}{\partial y}= (0,1,-2y)\\\\\displaystyle\frac{\partial G}{\partial x}\times\displaystyle\frac{\partial G}{\partial y}=(2x,2y,1)$

we also have

$\bf F(G(x,y))=F(x, y, 3-x^2-y^2)=(xy,y(3-x^2-y^2),x(3-x^2-y^2))=\\\\=(xy,3y-x^2y-y^3,3x-x^3-xy^2)$

and so

$\bf F(G(x,y))\cdot(\displaystyle\frac{\partial G}{\partial x}\times\displaystyle\frac{\partial G}{\partial y})=(xy,3y-x^2y-y^3,3x-x^3-xy^2)\cdot(2x,2y,1)=\\\\=2x^2y+6y^2-2x^2y^2-2y^4+3x-x^3-xy^2$

we just have then to compute a double integral of a polynomial on the unit square 0≤ x≤1 and 0≤ y≤1

$\bf \displaystyle\int_{0}^{1}\displaystyle\int_{0}^{1}(2x^2y+6y^2-2x^2y^2-2y^4+3x-x^3-xy^2)dxdy=\\\\=2\displaystyle\int_{0}^{1}x^2dx\displaystyle\int_{0}^{1}ydy+6\displaystyle\int_{0}^{1}dx\displaystyle\int_{0}^{1}y^2dy-2\displaystyle\int_{0}^{1}x^2dx\displaystyle\int_{0}^{1}y^2dy-2\displaystyle\int_{0}^{1}dx\displaystyle\int_{0}^{1}y^4dy+\\\\+3\displaystyle\int_{0}^{1}xdx\displaystyle\int_{0}^{1}dy-\displaystyle\int_{0}^{1}x^3dx\displaystyle\int_{0}^{1}dy-\displaystyle\int_{0}^{1}xdx\displaystyle\int_{0}^{1}y^2dy$

=1/3+2-2/9-2/5+3/2-1/4-1/6 = 2.794

5 0

3 years ago

What is the simplified form of expression<br> -4xy/3x

DiKsa [7]

Answer:

(-4/3)y

Step-by-step explanation:

The x cancels out, leaving:

-4y/3 or (-4/3)y

7 0

3 years ago