Ask question

Ask question

All categories

3 years ago

12

suppose Faye plans to fill packets with 60 beads and after deciding not to add any yellow beads (180 beads) to the mix. If you w

ant to find how many packets she can put together, what hidden questions or questions would you have to ask?? btw here are the color of beads and how many there are, red 195, blue 170, green 275, and yellow 180

1 answer:

Zolol [24]3 years ago

8 0

195+170+275=640, divided by 60 gets you about 10 and a half packets.

You might be interested in

what is the length of tw¯¯¯¯¯¯ ? segment t w with point u between t and w. segment t u is marked congruent to segment u w. segme

Gennadij [26K]

T________U________W
16
TU=UW
16=16
TW=TU+UW
TW=16+16
TW=32

6 0

3 years ago

Read 2 more answers

Item 3 is unpinned. Click to pin.

Ratling [72]

Answer:

84%

Step-by-step explanation:

i am so sorry if i am wrong. pls no hate tho

7 0

2 years ago

Read 2 more answers

Problem 4: Let F = (2z + 2)k be the flow field. Answer the following to verify the divergence theorem: a) Use definition to find

Viktor [21]

Given that you mention the divergence theorem, and that part (b) is asking you to find the downward flux through the disk $x^2+y^2\le3$ , I think it's same to assume that the hemisphere referred to in part (a) is the upper half of the sphere $x^2+y^2+z^2=3$ .

a. Let $C$ denote the hemispherical <u>c</u>ap $z=\sqrt{3-x^2-y^2}$ , parameterized by

$\vec r(u,v)=\sqrt3\cos u\sin v\,\vec\imath+\sqrt3\sin u\sin v\,\vec\jmath+\sqrt3\cos v\,\vec k$

with $0\le u\le2\pi$ and $0\le v\le\frac\pi2$ . Take the normal vector to $C$ to be

$\vec r_v\times\vec r_u=3\cos u\sin^2v\,\vec\imath+3\sin u\sin^2v\,\vec\jmath+3\sin v\cos v\,\vec k$

Then the upward flux of $\vec F=(2z+2)\,\vec k$ through $C$ is

$\displaystyle\iint_C\vec F\cdot\mathrm d\vec S=\int_0^{2\pi}\int_0^{\pi/2}((2\sqrt3\cos v+2)\,\vec k)\cdot(\vec r_v\times\vec r_u)\,\mathrm dv\,\mathrm du$

$\displaystyle=3\int_0^{2\pi}\int_0^{\pi/2}\sin2v(\sqrt3\cos v+1)\,\mathrm dv\,\mathrm du$

$=\boxed{2(3+2\sqrt3)\pi}$

b. Let $D$ be the disk that closes off the hemisphere $C$ , parameterized by

$\vec s(u,v)=u\cos v\,\vec\imath+u\sin v\,\vec\jmath$

with $0\le u\le\sqrt3$ and $0\le v\le2\pi$ . Take the normal to $D$ to be

$\vec s_v\times\vec s_u=-u\,\vec k$

Then the downward flux of $\vec F$ through $D$ is

$\displaystyle\int_0^{2\pi}\int_0^{\sqrt3}(2\,\vec k)\cdot(\vec s_v\times\vec s_u)\,\mathrm du\,\mathrm dv=-2\int_0^{2\pi}\int_0^{\sqrt3}u\,\mathrm du\,\mathrm dv$

$=\boxed{-6\pi}$

c. The net flux is then $\boxed{4\sqrt3\pi}$ .

d. By the divergence theorem, the flux of $\vec F$ across the closed hemisphere $H$ with boundary $C\cup D$ is equal to the integral of $\mathrm{div}\vec F$ over its interior:

$\displaystyle\iint_{C\cup D}\vec F\cdot\mathrm d\vec S=\iiint_H\mathrm{div}\vec F\,\mathrm dV$

We have

$\mathrm{div}\vec F=\dfrac{\partial(2z+2)}{\partial z}=2$

so the volume integral is

$2\displaystyle\iiint_H\mathrm dV$

which is 2 times the volume of the hemisphere $H$ , so that the net flux is $\boxed{4\sqrt3\pi}$ . Just to confirm, we could compute the integral in spherical coordinates:

$\displaystyle2\int_0^{\pi/2}\int_0^{2\pi}\int_0^{\sqrt3}\rho^2\sin\varphi\,\mathrm d\rho\,\mathrm d\theta\,\mathrm d\varphi=4\sqrt3\pi$

4 0

3 years ago

Emily can ride her scooter 18 miles in 50 minutes. a)how long would it take for her to ride 4 miles? b)what is her unit rate in

Blizzard [7]

Answer:A) At this same rate (speed) how far can she ride in two hours?

B) how long would it take for her to ride 4 miles?

C) what is her unit rate in miles per hour?

Step-by-step explanation:pls mark me as brainest pls

5 0

3 years ago

determine which sequence is an arithmatic sequence. a. -10, 5, - 5/2, 5/4,... b. 1/5, 1/7, 1/9, 1/11, ... c. 3,6, 12, 24,... d.

Damm [24]

Answer:

d

Step-by-step explanation:

An arithmetic sequence has a common difference between its terms. The only sequence with a common difference is choice d, which has a common difference of -4. The other options have common ratios, making them geometric, not arithmetic, sequences.

5 0

3 years ago