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OleMash [197]
4 years ago
13

The volume, V of gas varies inversely with the Pressure, P on it. If the volume is 320 cm3 under pressure of 40 kg/cm2, what pre

ssure has to be applied to have a volume of 200 cm3?
Mathematics
1 answer:
Pie4 years ago
5 0
Assuming that the gas behaves ideally.

Given the initial volume and pressure:

V1 = 320 cm3
P1 = 40 kg/cm2

and given the final volume:

V2 = 200 cm3

find the final pressure, P2:

PV = nRT; assume temperature and number of moles are constant

PV = constant

P1V1 = P2V2

Solve for P2:

(320 cm3) (40 kg/cm2) = (200 cm3) (P2)

P2 = 64 kg/cm2
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A line has a slope of -4 and a y-intercept of 1. What is the equation of the line in slope-intercept form?
Anastaziya [24]
The answer is B because the equation is y=mx+b, where m is the slope and b is the y intercept. In this case m or the slope is -4 and the b or the y intercept is 1 so then just substitute them in and there is your answer
4 0
4 years ago
What is the estimated ansewr for 318×3
Finger [1]
I would estimate this around 960 since 318 is close to 320 and 320x3 is 960, the actual answer would be 3x318 which is 954.
7 0
4 years ago
Read 2 more answers
OA=<br> Please help asap!! Thanks so much :))
Mashcka [7]

In the given diagram, the value of the dashed side of rhombus OABC is 5

<h3>Distance between two points </h3>

From the question, we are to determine the length of the dashed line (OA), in rhombus OABC

In the diagram, we can observe that the length of OA is the distance between point A and the origin (O).

Using the formula for calculating distance between two points,

d =√[(x₂-x₁)² + (y₂-y₁)²]

In the diagram,

The coordinate of the origin is (0, 0)

The coordinate of point A is (3, 4)

Thus,

x₁ = 0

x₂ = 3

y₁ = 0

y₂ = 4

Putting the parameters into the formula, we get

OA =√[(3-0)² + (4-0)²]

OA =√(3² + 4²)

OA =√(9+16)

∴ OA =√25

OA = 5

Hence, in the given diagram, the value of the dashed side of rhombus OABC is 5

Learn more on Distance between two points here: brainly.com/question/24778489

#SPJ1

5 0
2 years ago
How do I find the ration of the first number to the second and simplify?<br> 0.4 to 1.2
Ivanshal [37]

Answer:

1:3

Step-by-step explanation:

it is a bit easy to get it out of decimal ratio, so multiply it by 10, which gives you 4:12, so now you have a bigger answer to work with, you can divide 12 by 4, which gives you 3, and a ratio of 1:3

5 0
4 years ago
Read 2 more answers
g Gravel is being dumped from a conveyor belt at a rate of 10 ft3/min, and its coarseness is such that it forms a pile in the sh
Maslowich

Answer:

0.3537 feet per minute.

Step-by-step explanation:

Gravel is being dumped from a conveyor belt at a rate of 10 ft3/min. Since we are told that the shape formed is a cone, the rate of change of the volume of the cone.

\dfrac{dV}{dt}=10$ ft^3/min

\text{Volume of a cone}=\dfrac{1}{3}\pi r^2 h

If the Base Diameter = Height of the Cone

The radius of the Cone = h/2

Therefore,

\text{Volume of the cone}=\dfrac{\pi h}{3} (\dfrac{h}{2}) ^2 \\V=\dfrac{\pi h^3}{12}

\text{Rate of Change of the Volume}, \dfrac{dV}{dt}=\dfrac{3\pi h^2}{12}\dfrac{dh}{dt}

Therefore: \dfrac{3\pi h^2}{12}\dfrac{dh}{dt}=10

We want to determine how fast is the height of the pile is increasing when the pile is 6 feet high.

When h=6$ feet$\\\dfrac{3\pi *6^2}{12}\dfrac{dh}{dt}=10\\9\pi \dfrac{dh}{dt}=10\\ \dfrac{dh}{dt}= \dfrac{10}{9\pi}\\ \dfrac{dh}{dt}=0.3537$ feet per minute

When the pile is 6 feet high, the height of the pile is increasing at a rate of 0.3537 feet per minute.

7 0
4 years ago
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