The volume, V of gas varies inversely with the Pressure, P on it. If the volume is 320 cm3 under pressure of 40 kg/cm2, what pre
ssure has to be applied to have a volume of 200 cm3?
1 answer:
Assuming that the gas behaves ideally.
Given the initial volume and pressure:
V1 = 320 cm3
P1 = 40 kg/cm2
and given the final volume:
V2 = 200 cm3
find the final pressure, P2:
PV = nRT; assume temperature and number of moles are constant
PV = constant
P1V1 = P2V2
Solve for P2:
(320 cm3) (40 kg/cm2) = (200 cm3) (P2)
P2 = 64 kg/cm2
You might be interested in
Answer:
Step-by-step explanation:
plug 3 into x
2(3)^2+(3)
2(9)+3
18+3
21
f(3)=21
The line that is most likely to have a slope of 10 is the second one down
Let the number be n.
Then 3n+5 = n+40
Combining like terms, we get
2n = 35, and so n = 35/7, or 17 1/2.
Answer:
= 
Step-by-step explanation:
given 5y = 3x ( divide both sides by 3 )
y = x ( divide both sides by y )
=
