Evaluate f(x) = x2 + 1 for f(10).

karen brought 3/8 of a gallon of ice tea to a party. Robin brought 15/16 of a gallon of ice tea to the same party. How much ice

Rudiy27

Answer:

1 5/16 gallon

Step-by-step explanation:

Gallon of ice brought by Karen = 3/8

Gallon of ice brought by Robin = 15/16

Total ice team brought by them is sum of Gallon of ice brought by Karen + Gallon of ice brought by Robin

Total ice team brought by Karen and Robin = 3/8 + 15/16

=> 3*2/8*2 + 15/16

we are multiplying with 2 both numerator and denominator in 3/8 so sas the denominator becomes 16 as in other fraction denominator is 16

=> 6/16 + 15/16

=> (6+15)/16 = 21/16

since 21/16 is improper fraction, converting it in mixed fraction we have

21/16 = 1 5/16 gallon

Thus , Karen and Robin have 1 5/16 gallon ice tea together.

7 0

3 years ago

Please need help thank you

lilavasa [31]

Answer: 7

How many took 7.5 OR less. This means it includes the hikes that took 7.5 hours. Count all of the ones that start from 7.5 and lower

6 0

3 years ago

Suppose that two openings on an appellate court bench are to be filled from current municipal court judges. The municipal court

Ksju [112]

Answer:

$(a)\dfrac{92}{117}$

$(b)\dfrac{8}{39}$

$(c)\dfrac{25}{117}$

Step-by-step explanation:

Number of Men, n(M)=24

Number of Women, n(W)=3

Total Sample, n(S)=24+3=27

Since you cannot appoint the same person twice, the probabilities are <u>without replacement.</u>

(a)Probability that both appointees are men.

$P(MM)=\dfrac{24}{27}X \dfrac{23}{26}=\dfrac{552}{702}\\=\dfrac{92}{117}$

(b)Probability that one man and one woman are appointed.

To find the probability that one man and one woman are appointed, this could happen in two ways.

A man is appointed first and a woman is appointed next.
A woman is appointed first and a man is appointed next.

P(One man and one woman are appointed) $=P(MW)+P(WM)$

$=(\dfrac{24}{27}X \dfrac{3}{26})+(\dfrac{3}{27}X \dfrac{24}{26})\\=\dfrac{72}{702}+\dfrac{72}{702}\\=\dfrac{144}{702}\\=\dfrac{8}{39}$

(c)Probability that at least one woman is appointed.

The probability that at least one woman is appointed can occur in three ways.

A man is appointed first and a woman is appointed next.
A woman is appointed first and a man is appointed next.
Two women are appointed

P(at least one woman is appointed) $=P(MW)+P(WM)+P(WW)$

$P(WW)=\dfrac{3}{27}X \dfrac{2}{26}=\dfrac{6}{702}$

In Part B, $P(MW)+P(WM)=\frac{8}{39}$

Therefore:

$P(MW)+P(WM)+P(WW)=\dfrac{8}{39}+\dfrac{6}{702}\\$P(at least one woman is appointed)=\dfrac{25}{117}$

5 0

3 years ago

What ratio can be used to calculate the geometric mean of 6 and 42?

Aleksandr [31]

The ratio...i think they answer is idk

3 0

3 years ago

BEST ANSWER GETS BRAINLIESTT!! PLEASE HELP

Sphinxa [80]

The answer would be the median is 10 because if u actually take the time and draw it you x everything out and see whats in the middle and you will have 10 dots lolz hope this helped

5 0

3 years ago

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