PLEASE HELP ME!!!!!!

Mathematics

1 answer:

Harrizon [31]3 years ago

7 0

65-26
A = 200(1+(0.0275/12)^0.0275(12 x 41 ) graph this in y =

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4. Write an equation for the line that is parallel to the given line and that passes

pentagon [3]

Answer:

$y=\frac{5}{2}x-14$

Step-by-step explanation:

Hi there!

What we need to know:

Linear equations are typically organized in slope-intercept form: $y=mx+b$ where m is the slope and b is the y-intercept (the value of y when x is 0)
Parallel lines always have the same slope

1) Determine the slope (m)

$y=\frac{5}{2}x-10$

In the given equation, $\frac{5}{2}$ is in the place of m, making it the slope. Because parallel lines have the same slope, the line we're currently solving for therefore has a slope of $\frac{5}{2}$ . Plug this into $y=mx+b$ :

$y=\frac{5}{2}x+b$

2) Determine the y-intercept (b)

$y=\frac{5}{2}x+b$

Plug in the given point (-6,-29) and solve for b

$-29=\frac{5}{2}(-6)+b$

Simplify -6 and 2

$-29=\frac{5}{1}(-3)+b\\-29=(5)}(-3)+b\\-29=-15+b$

Add 15 to both sides to isolate b

$-29+15=-15+b+15\\-14=b$

Therefore, the y-intercept is -14. Plug this back into $y=\frac{5}{2}x+b$ :

$y=\frac{5}{2}x-14$

I hope this helps!

4 0

3 years ago

Help me find the scale factor

atroni [7]

The scale factor for the first one is 2.25
And for the second one it’s 7
I hope this helps :)

3 0

3 years ago

Please i need your help...Thanks

pishuonlain [190]

Lol I’m not sure but I’m logging in so it’s making me “answer”

8 0

3 years ago

To hang lights up on his house.Garrett place is a 14 foot ladder 4 feet from the base of the house. How high up the house will t

Firlakuza [10]

This seems like a right triangle problem.

So assuming 14 feet is the hypotenuse and 4 feet is a leg of the right triangle, we can use the pythagorean theorem ( $a^{2} +b^{2} =c^{2}$ ) to solve for the height of the house, in which we shall name it x.