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Verizon [17]
3 years ago
9

Can someone help please !

Mathematics
2 answers:
stealth61 [152]3 years ago
7 0
Ramp 2=35
Ramp 1=8.............
34kurt3 years ago
3 0

Answer:

Ramp 2=35

Ramp 1=8.............

Step-by-step explanation:

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Find the GCF of 18xy and 32xyz<br><br> If you answer my question you will recieve 35 points
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There is one 2 in common and there are "x" and "y" variables in common. Finally, the GCF of 18xy and 32xyz is 2xy.
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If 10 oranges cost 2.00 and 8 oranges cost 1.20 which is the better deal
s344n2d4d5 [400]

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10 oranges

Step-by-step explanation:

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3 years ago
Solve the equation for all real solutions in simplest form.<br>3v2 + 6v +1 = 0​
kirill [66]

Answer:

v = − 3 ± √ 6/ 3

Step-by-step explanation:

hope this helps plz put me as brainiest

7 0
3 years ago
Seven members of a Girl Scout troop report the following individual earnings from their sale of candy: $4, $1, $7, $6, $8, $2, a
Radda [10]

Answer:

(B) the mean is less than the mode and less than the median.

Step-by-step explanation:

Mean, Median, Mode is used to calculate the central tendency of the distribution.

Mean is defined as,

Mean = \dfrac{Sum of all observation}{Total number of observation}\\ \ \ \ \ \ \ \ \ = \dfrac{4+1+7+6+8+2+7}{7}

∴ Mean = 5

Median is the middle observation of the distribution after arranging it in ascending or descending order.

So, arranging distribution in ascending order we get,

$1, $2, $4, $6, $7, $7, $8

Also, a number of observation is 7 which is an odd number.

Hence, Median = (\frac{Number of observation + 1}{2})^{th} term

⇒ Median = (\frac{7 + 1}{2})^{th} term

⇒ Median = 4th term = 6

Mode is the observation which has highest frequency.

Here, only $7 is repeated 2 times.

Hence, Mode = 7.

Hence, we see that Mean < Median < Mode

So, Option (B) is correct i.e. mean is less than the mode and less than the median.

8 0
4 years ago
How many cases does he hear if his hears 5 cases every 2 3/5
vekshin1
How many cases does he hear if he hears 5 cases every 2 3/5 what?

Days?

Weeks?

Months?

Years?
8 0
3 years ago
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