Complete Question
Talia attended a 5 -day math camp that lasted 5/6 of an hour each day. How many hours did Talia spend at the math camp?
Answer:
4 1/6 hours
Step-by-step explanation:
1 day = 5/6 hour
5 days = x
Cross Multiply
x = 5/6 × 5 days
x = 25/6 hours
x = 4 1/6 hours
Therefore, Talia spent 4 1/6 hours at camp.
A coyote had 10 pups in her third litter. (10)
It was twice as many as in her second litter,( 2( second litter) = third litter
her second litter had 3 more pups than her first.( first litter +3)=2nd litter
Find the number of pups in her litter
Answer:
a) 95% confidence interval estimate of the true weight is (3.026, 3.274)
b) 99% confidence interval estimate of the true weight is (2.944, 3.356)
Step-by-step explanation:
Confidence Interval can be calculated using M±ME where
- M is the mean of five successive weightings (3.150)
- ME is the margin of error from the mean
And margin of error (ME) can be calculated using the formula
ME=
where
- t is the corresponding statistic in the given confidence level and degrees of freedom(t-score)
- s is the standard deviation of the random error (0.1)
Using the numbers 95% confidence interval estimate of the true weight is:
3.150±
≈3.150±0.124
And 99% confidence interval estimate of the true weight is:
3.150±
≈3.150±0.206
Assuming that the missing operations are multiplication as it is with the first question "bd", then the answer would be as follows:
1.) Simply substitute the values of b and d before multiplying.
bd = (-2)(-6) = 12
2.) (-50)(-2) = 100
3.) (5/8)(7/12)= 35/96
Answer:
3,1,2
Step-by-step explanation:
I think it is 3,1,2 but I'm not completely sure lmk if it's correct or incorrect
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