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snow_lady [41]
3 years ago
8

Whats an"an amount, shared equally with 4 people " ​

Mathematics
1 answer:
aleksley [76]3 years ago
6 0

well if that's in a math problem then its division. Because you are sharing equally.

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Pl help it’s for a grade
allsm [11]

Answer:

(^6√x^5) (√y)

(The 6 belongs in the left on top of the square root btw)

For x the 6 moves to the front of the square root while the 5 becomes the power of x.

For y, the power to the 1/2 is the same as a square root.

5 0
3 years ago
Which of the following is equivalent to 60 g?​
guajiro [1.7K]

Answer:

The number of cups that are equivalent to 60 grams varies based on what is being measured.

Step-by-step explanation:

j

5 0
3 years ago
Evaluate using inverse operations...<br><br> 9x + 8 = 27
melomori [17]

Answer:

9x+8=27

9x=27_8

9x=19

9 9

x=2.111111111111

5 0
2 years ago
Read 2 more answers
What is the value of x
FromTheMoon [43]

Answer:

x = 32

Step-by-step explanation:

this is an equilateral triangle where all sides measure the same value; therefore, 2x-4 = 5y

since we are solving for 'x' we can set up this equation:

3(2x-4) = 180

6x - 12 = 180

6x = 192

x = 32

4 0
2 years ago
Use sigma notation to represent the sum of the first seven terms of the following sequence -4,-6,-8.....
lina2011 [118]

Answer:Answer:

\sum\left {{7} \atop {1}} \right -n(3+n)

Step-by-step explanation:

Given the sequence -4,-6,-8..., in order to get sigma notation to represent the sum of the first seven terms of the sequence, we need to first calculate the sum of the first seven terms of the sequence as shown;

The sum of an arithmetic series is expressed as S_n = \frac{n}{2}[2a+(n-1)d]

n is the number of terms

a is the first term of the sequence

d is the common difference

Given parameters

n = 7, a = -4 and d = -6-(-4) = -8-(-6) = -2

Required

Sum of the first seven terms of the sequence

S_7 = \frac{7}{2}[2(-4)+(7-1)(-2)]\\\\S_7 =  \frac{7}{2}[-8+(6)(-2)]\\\\S_7 =  \frac{7}{2}[-8-12]\\\\\\S_7 = \frac{7}{2} * -20\\\\S_7 = -70

The sum of the nth term of the sequence will be;

S_n = \frac{n}{2}[2(-4)+(n-1)(-2)]\\\\S_n = \frac{n}{2}[-8+(-2n+2)]\\\\S_n = \frac{n}{2}[-6-2n]\\\\S_n =  \frac{-6n}{2} -  \frac{2n^2}{2}\\S_n = -3n-n^2\\\\S_n = -n(3+n)

The sigma notation will be expressed as \sum\left {{7} \atop {1}} \right -n(3+n). <em>The limit ranges from 1 to 7 since we are to  find  the sum of the first seven terms of the series.</em>

3 0
3 years ago
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