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faltersainse [42]
3 years ago
13

What is the factorization of the polynomial below? -x^2-15x-56

Mathematics
1 answer:
stellarik [79]3 years ago
7 0

Answer:

Option C. (x+8)(x+7)

Step-by-step explanation:

we have

-x^2-15x-56

Find the roots of the quadratic equation

equate the equation to zero

-x^2-15x-56=0

The formula to solve a quadratic equation of the form

ax^{2} +bx+c=0

is equal to

x=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}

in this problem we have

-x^2-15x-56=0

so

a=-1\\b=-15\\c=-56

substitute in the formula

x=\frac{-(-15)\pm\sqrt{-15^{2}-4(-1)(-56)}} {2(-1)}

x=\frac{15\pm\sqrt{1}} {-2}

x=\frac{15\pm1} {-2}

x=\frac{15+1} {-2}=-8

x=\frac{15-1} {-2}=-7

The roots are

x=-8 and x=-7

so

The quadratic equation in factored form is equal to

-x^2-15x-56=(x+8)(x+7)

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