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Rasek [7]
3 years ago
5

Determine the solution to the following system of equations: 2x+4y=-12 x+2y=-2

Mathematics
2 answers:
slavikrds [6]3 years ago
8 0

Answer: The answer is no solution.


Step-by-step explanation:

First you want to isolate x.

  x=-2(y+3)

Then you substitute.

  [-2(y+3)+2y=-2]

Then you refine.

  -4=0

As you can see -4 isn't equal to 0, therefore this system is false. Which is where we get the answer no solution.  


jolli1 [7]3 years ago
4 0

Answer:

undefined/no solution

Step-by-step explanation:

you use elimination to solve. So multiply 2x+4y=-12 by 1 and x+2y=-2 by 2. then you subtract 2x+4y=-12 by 2x+4y=-4 and get 0y=-8. Anything divided by 0 is undefined/no solution because you can't divide anything by 0.

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What must be added to both sides in 4x² + 24x + 8 = 32 in order to complete the square?
Sergeu [11.5K]

Answer:

16

Step-by-step explanation:

To solve a quadratic equation by using the completing the square method, the coefficient of the square term i.e x² must be one (1).

Therefore, we would have to first make the coefficient of x² to be equal to 1.

4x² + 24x + 8 = 32

We would simplify the equation;

4x² + 24x = 32 - 8

4x² + 24x = 24

Divide all through by 4;

x² + 8x = 24

The value to be added = (8/2)² = 4² = 16

x² + 8x + 16 = 8 + 16

x² + 4x + 4x + 16 = 24

x(x + 4) + 4(x + 4) = 24

(x + 4)² = 24

Taking the square root of both sides;

x + 4 = ± 4.9

x = -4 ± 4.9

x = -4 + 4.9 = 0.9

or

x = -4 - 4.9 = - 8.9

<em>Therefore, 16 must be added to solve the quadratic equation by completing the square method. </em>

6 0
3 years ago
Can someone please help me ASAP​
Sonja [21]

Answer:

x^2 + 5n = 4mx

=> x^2 - 4mx + 5n = 0

D=0 (since one root then roots are equal)

b^2-4ac = 0

(-4m)^2 - 4(1)(5n) = 0

16m^2 - 20n = 0

16m^2 = 20n

8m^2 = 10n

4m^2 = 5n

hope it helps.......

7 0
2 years ago
write about which method you prefer to use to divide by 5 counting up, counting back on a number line, or dividing by 10, and th
maria [59]

Answer:

In First method : counting up, counting back on a number line,

If we want the quotient after dividing the number by 5 then we count how many 5 we get from 0 to the dividend.

For example :  \frac{30}{5}

Since, from 0 to 30 there are six 5's obtained. ( because 5 × 6 = 30 )

Thus,  \frac{30}{5}=6

In Second Method : dividing by 10, and then doubling the quotient.

First we divide the number by 10 then multiply the quotient by 2.

For Example: \frac{30}{5}

Since, \frac{30}{10}=3

2\times 3 = 6

Thus, \frac{30}{5}=6

Now, when we compare the above methods then we conclude that for the smaller numbers first method is appropriate because for small numbers we can easily count total 5's from 0. While for large numbers Second method is appropriate because it is hard to count the total 5's for the large number.


4 0
3 years ago
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Tema [17]

Answer:

SAS

Step-by-step explanation:

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