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3 years ago

Determine the solution to the following system of equations: 2x+4y=-12 x+2y=-2

Mathematics

2 answers:

slavikrds [6]3 years ago

8 0

Answer: The answer is no solution.

Step-by-step explanation:

First you want to isolate x.

x=-2(y+3)

Then you substitute.

[-2(y+3)+2y=-2]

Then you refine.

-4=0

As you can see -4 isn't equal to 0, therefore this system is false. Which is where we get the answer no solution.

jolli1 [7]3 years ago

4 0

Answer:

undefined/no solution

Step-by-step explanation:

you use elimination to solve. So multiply 2x+4y=-12 by 1 and x+2y=-2 by 2. then you subtract 2x+4y=-12 by 2x+4y=-4 and get 0y=-8. Anything divided by 0 is undefined/no solution because you can't divide anything by 0.

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Answer: $0=2x^2-7x-9\\0=4x^2-3x-1\\0=x^2-2x-8$

Step-by-step explanation:

We know that the standard quadratic equation is ax^2+bx+c=0

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2. a=1, b=-4, c=4

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So it has 2 real number solutions.

4. a=1, b=-2, c=-8

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So it has 2 real number solutions.

5. a=3, b=5, c=3

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Thus it does not has real solutions.

5 0

2 years ago

Read 2 more answers

Please help? It's worth 16 points!!!!

ddd [48]

Answer:

I’m not too sure what your question is exactly but if your just trying to graph the two equations I can help u with that (:

Step-by-step explanation:

The first thing you should do is change the second equation to slope intercept form. It is much easier for most people. From there write out your table by choosing a number for x then plugging that number into the equation to find y. For the first equation (y=1/3x+2) it’s always easier to use multiple of three for the number of x. For example, if 3 was my number for x I would multiply 1/3 by 3=1 then simply add 2=3. So the coordinates for one point on that table would be 3,3. You continue to do that for each graph then plot your points. (In my graph, purple is the equation y+9=-9/3x-9 and black equals the equation y=1/3x+2

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