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Over [174]
3 years ago
8

Determine the function f(x) satisfying the given conditions.

Mathematics
1 answer:
Furkat [3]3 years ago
8 0
<span>f''(x) means function is of grade 1
f(x) = ax + b

f'(x) = a
f'(5) = 1 </span>⇒ a = 1

f(4) = -2
f(4) = 1×4 + b
-2 = 4 + b
b = -6

f(x) = x - 6
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(sec(π/3) + tan(-7π/4))/(1-cos(2 π/3))
Paha777 [63]

Answer:

3

Step-by-step explanation:

3+3_3=3

after that 3+2+6+7+7+8+8+9+9+9+9+9+0+0+8+6+5+4+ 5=?

u will do the answer and it will be done

6 0
3 years ago
Read 2 more answers
Find the value.<br><br> A.<br> 1<br><br> B.<br> 2<br><br> C.<br> 3<br><br> D.<br> 0.5
Ksju [112]
The cube root is 1
The Answer is A. 1
4 0
3 years ago
Kaylee invested $910 in an account paying an interest rate of 2.6% compounded
Nikitich [7]

Answer:

$1,179

Step-by-step explanation:

Lets use the compound interest formula provided to solve this:

A=P(1+\frac{r}{n} )^{nt}

<em>P = initial balance</em>

<em>r = interest rate (decimal)</em>

<em>n = number of times compounded annually</em>

<em>t = time</em>

<em />

First, lets change 2.6% into a decimal:

2.6% -> \frac{2.6}{100} -> 0.026

Since the interest is compounded quarterly, we will use 4 for n. Lets plug in the values now:

A=910(1+\frac{0.026}{4})^{4(10)}

A=1,179.21

The account balance after 10 years will be $1,179

8 0
3 years ago
The center of the circle is at (-2,-7) and its radius is 36.
Vanyuwa [196]
Standard form for circle with radius r and center (h,k) is
(x-h)^2+(y-k)^2=r^2

r=36
center at -2,-7
(x-(-2))^2+(y-(-7))^2=36^2
(x+2)^2+(y+7)^2=1296


firts option
6 0
3 years ago
Simplify the expression: 2(4 + 6j)
aniked [119]

Answer:

\boxed{ \bold{ \huge{ \boxed{ \sf{8 + 12j}}}}}

Step-by-step explanation:

\sf{2(4 + 6j)}

Distribute 2 through the parentheses

\longrightarrow{ \sf{2 \times 4  + 2 \times 6j}}

\longrightarrow{ \sf{8  + 12j}}

Hope I helped!

Best regards! :D

8 0
3 years ago
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