What is 2.5t=10 <br> T is variable

A box of laundry detergent is on sale for $6.50. If this price represents a 40% discount from the original price, what is the or

Mademuasel [1]

$10.83 because you need to divide 6.50 by .6 to get that answer approximately.

4 0

3 years ago

Find f(-5) if f( x ) = | x + 1|.

Alekssandra [29.7K]

Answer:

Step-by-step explanation:

f(x)=x+1

then,

f(-5)=(-5)+1

=-4

8 0

2 years ago

The math problem is 100 x 0.496

Setler79 [48]

Answer:

49.6

Step-by-step explanation:

To multiply a power of (ten) 10 by a decimal all you have to do is move the decimal point the number of zeros (0) in the power of 1 to the right.

So to do this equation you move the decimal point in 0.496 you move the decimal point two (2) times to the right to get 49.6.

3 0

2 years ago

Read 2 more answers

Quantitative noninvasive techniques are needed for routinely assessing symptoms of peripheral neuropathies, such as carpal tunne

Pavlova-9 [17]

Answer:

$t=\frac{2.35-1.83}{\sqrt{\frac{0.88^2}{10}+\frac{0.54^2}{7}}}}=1.507$

$p_v =P(t_{(15)}>1.507)=0.076$

If we compare the p value and the significance level given $\alpha=0.01$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and the group CTS, NOT have a significant higher mean compared to the Normal group at 1% of significance.

Step-by-step explanation:

1) Data given and notation

$\bar X_{CTS}=2.35$ represent the mean for the sample CTS

$\bar X_{N}=1.83$ represent the mean for the sample Normal

$s_{CTS}=0.88$ represent the sample standard deviation for the sample of CTS

$s_{N}=0.54$ represent the sample standard deviation for the sample of Normal

$n_{CTS}=10$ sample size selected for the CTS

$n_{N}=7$ sample size selected for the Normal

$\alpha=0.01$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the mean for the group CTS is higher than the mean for the Normal, the system of hypothesis would be:

Null hypothesis: $\mu_{CTS} \leq \mu_{N}$

Alternative hypothesis: $\mu_{CTS} > \mu_{N}$

If we analyze the size for the samples both are less than 30 so for this case is better apply a t test to compare means, and the statistic is given by:

$t=\frac{\bar X_{CTS}-\bar X_{N}}{\sqrt{\frac{s^2_{CTS}}{n_{CTS}}+\frac{s^2_{N}}{n_{N}}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other".

Calculate the statistic

We can replace in formula (1) the info given like this:

$t=\frac{2.35-1.83}{\sqrt{\frac{0.88^2}{10}+\frac{0.54^2}{7}}}}=1.507$

P-value

The first step is calculate the degrees of freedom, on this case:

$df=n_{CTS}+n_{N}-2=10+7-2=15$

Since is a one side right tailed test the p value would be:

$p_v =P(t_{(15)}>1.507)=0.076$

We can use the following excel code to calculate the p value in Excel:"=1-T.DIST(1.507,15,TRUE)"

Conclusion

If we compare the p value and the significance level given $\alpha=0.01$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and the group CTS, NOT have a significant higher mean compared to the Normal group at 1% of significance.

6 0

3 years ago

Some money is shared between erin, faye and sachin in the ratio 5:2:7. Faye gets £90 less than sachin. How much money did Erin g

VARVARA [1.3K]

Answer:

Erin gets £90

Step-by-step explanation:

Ratio = 5 : 2 : 7

Money with Erin = 5x

Money with Faye = 2x

Money with Sachin = 7x

Faye gets £90 less than Sachin

7x - 2x = 90

5x = 90

x = 90/5

x = 18

Money with Erin = 5*18 = 90

7 0

3 years ago

What is 2.5t=10 T is variable