Answer:
a) No
b) No
c) P value is more than 0.05.
Step-by-step explanation:
We are given the following in the question:
Population mean, μ = 12 ounces
Sample size, n = 49
P-value = 0.136
First, we design the null and the alternate hypothesis
We use One-tailed z test to perform this hypothesis.
a) Alpha, α = 0.05
Since, p-value > α,
The null hypothesis should not be rejected. We accept the null hypothesis and reject the alternate hypothesis. We conclude that the average chip weight is 12 ounces per bag.
b) Alpha, α = 0.10
Since, p-value > α,
The null hypothesis should not be rejected. We accept the null hypothesis and reject the alternate hypothesis. We conclude that the average chip weight is 12 ounces per bag.
c) The evidence is statistically significant at the .05 level means that the p value is more than 0.05.
Answer:
The complement is 53 and the supplement is 143
Step-by-step explanation:
Two complementary angles add to 90
PQR and x = 90
37+x = 90
Subtract 37 from each side
37-37 +x =90-37
x = 53
The complement is 53
Two supplementary angles add to 180 degrees
PQR and x = 180
37+x = 180
Subtract 37 from each side
37-37 +x= 180-37
x = 143
The supplement is 143
11, rosabell had 11 posters for the parade