The product of 2 and the difference of 3 and X
Hope I could help :)
Answer:
A
Step-by-step explanation:
Been a while since i’ve done this but I’ pretty sure since A starts on 2 and goes back 7 (into the negatives for minus 7) it would be A.
Answer:
D
Step-by-step explanation:
Let's see if the lengths of these two segments are the same or not. We will use the distance formula, which says that for two points
and
, the distance between them is:
.
For AB,
is (-9, 12) and
is (3, -6). So, the distance is:
![=6\sqrt{13}](https://tex.z-dn.net/?f=%3D6%5Csqrt%7B13%7D)
For A'B',
is (-3, 4) and
is (1, -2). So, the distance is:
![\sqrt{(-3-1)^2+(4-(-2))^2}=\sqrt{(-4)^2+(6)^2} =\sqrt{16+36} =\sqrt{52}=2\sqrt{13}](https://tex.z-dn.net/?f=%5Csqrt%7B%28-3-1%29%5E2%2B%284-%28-2%29%29%5E2%7D%3D%5Csqrt%7B%28-4%29%5E2%2B%286%29%5E2%7D%20%3D%5Csqrt%7B16%2B36%7D%20%3D%5Csqrt%7B52%7D%3D2%5Csqrt%7B13%7D)
We can see that
is 3 times of
, which means that AB (the original) is 3 times the length of A'B' (the transformed).
Since the length has changed, we know that it must be some sort of dilation because that's the only kind of transformation that will change the length. We see that the segment has also shortened, which means that its scale factor must be less than 1.
The only answer that matches is D.
Hope this helps!
To solve this problem you must apply the proccedure shown below:
1. Let's call
to the number of boxes of chocolate.
2. You have that he spends for month:
![1500dollars+6000dollars=7500dollars](https://tex.z-dn.net/?f=%201500dollars%2B6000dollars%3D7500dollars%20)
3. The problem says that Jeremy prices his chocolates at
the piece and offers a discount of
% on boxes of chocolate. Therefore, the price of a box is:
![36dollars-(36dollars)(0.1)=32.4dollars](https://tex.z-dn.net/?f=%2036dollars-%2836dollars%29%280.1%29%3D32.4dollars%20)
4. Therefore, you can write the following equation and solve for
:
The answer is:
boxes of chocolate.
I believe the answer is 2