Replace x with the binomial a - 2.
f(a - 2) = [3(a - 2) + 5]/(a- 2)
f(a - 2) = [3a - 6 + 5]/(a - 2)
f(a - 2) = [3a - 1]/(a - 2)
f(a - 2) = (3a - 1)/(a - 2)
Done.
Answer:
It would be the graph that has point (0,12) and is decreasing to the right.
I'm not sure but I think it is
4.48×10 10 <---this to is an exponent
We have to round each whole number to the given place value.
We have to round the number 437 to the tens place.
Since the digit at the tens place is 3.
Since the digit at its previous place that is ones place is '7' which is greater than 5.
Therefore, we can round the number 437 to 440.
Now, consider the another number 64,328, we have to round this number to the nearest ten thousand place.
Since the digit at ten thousands place is 6.
And the digit at its previous place that is, at thousands place is 4.
Since this number is less than 5.
Therefore, the given number will round to 60,000.
Given the equation:
We will use the following rule to find the solution to the equation:
![x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B-b%5Cpm%5Csqrt%5B%5D%7Bb%5E2-4ac%7D%7D%7B2a%7D)
From the given equation: a = 6, b = 7, c = 2
So,
![\begin{gathered} x=\frac{-7\pm\sqrt[]{7^2-4\cdot6\cdot2}}{2\cdot6}=\frac{-7\pm\sqrt[]{1}}{12}=\frac{-7\pm1}{12} \\ x=\frac{-7-1}{12}=-\frac{8}{12}=-\frac{2}{3} \\ or,x=\frac{-7+1}{12}=-\frac{6}{12}=-\frac{1}{2} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20x%3D%5Cfrac%7B-7%5Cpm%5Csqrt%5B%5D%7B7%5E2-4%5Ccdot6%5Ccdot2%7D%7D%7B2%5Ccdot6%7D%3D%5Cfrac%7B-7%5Cpm%5Csqrt%5B%5D%7B1%7D%7D%7B12%7D%3D%5Cfrac%7B-7%5Cpm1%7D%7B12%7D%20%5C%5C%20x%3D%5Cfrac%7B-7-1%7D%7B12%7D%3D-%5Cfrac%7B8%7D%7B12%7D%3D-%5Cfrac%7B2%7D%7B3%7D%20%5C%5C%20or%2Cx%3D%5Cfrac%7B-7%2B1%7D%7B12%7D%3D-%5Cfrac%7B6%7D%7B12%7D%3D-%5Cfrac%7B1%7D%7B2%7D%20%5Cend%7Bgathered%7D)
So, the answer will be option B) x = -1/2, -2/3
