Answer:
Perimeter = 60ft = 2(4x + x)
breadth = 6ft
length = 24ft
Step-by-step explanation:
Perimeter = 2 (L + B)
L =length
B = Breadth
x= breadth
4x = length
Perimeter = 60ft = 2(4x + x)
Dividing both sides by 2 :
30ft= 4x + x
30ft = 5x
divide both sides by 5
6ft= x
breadth = 6ft
length = 4x= 4 x 6 = 24ft
Answer:
1.
Part A: Yes, it is (a - b)².
Part B: a² - 2ab + b² => (x - 6)² = x² - 12x + 36.
Part C: x² - 12x + 36.
2.
Part A: Not a special product.
Part B: Binomial distribution => (x + 8)(x + 1) = x² + 9x + 8.
Part C: x² + 9x + 8.
3.
Part A: Yes, it is (a + b)²
Part B: a² + 2ab + b² => (3x + 2)² = 9x² + 12x + 4.
Part C: 9x² + 12x + 4.
4.
Part A: Yes, it is (a + b)(a - b), a difference of squares.
Part B: a² - b² => 4x² - 49
Part C: 4x² - 49.
5.
Part A: Not a special product.
Part B: Binomial distribution => (x - 5)(2x - 5) = 2x² - 15x + 25.
Part C: 2x² - 15x + 25.
The function of the area of the square is A(t)=121![t^{2}](https://tex.z-dn.net/?f=t%5E%7B2%7D)
Given that The length of a square's sides begins at 0 cm and increases at a constant rate of 11 cm per second. Assume the function f determines the area of the square (in cm2) given several seconds, t since the square began growing and asked to find the function of the area
Lets assume the length of side of square is x
11 ![\frac{cm}{sec}](https://tex.z-dn.net/?f=%5Cfrac%7Bcm%7D%7Bsec%7D)
⇒x=11t
Area of square=![(length of side)^{2}](https://tex.z-dn.net/?f=%28length%20of%20side%29%5E%7B2%7D)
Area of square=
{as the length of side is 11t}{varies by time}
Area of square=121![t^{2}](https://tex.z-dn.net/?f=t%5E%7B2%7D)
Therefore,The function of the area of the square is A(t)=121![t^{2}](https://tex.z-dn.net/?f=t%5E%7B2%7D)
Learn more about The function of the area of the square is A(t)=121![t^{2}](https://tex.z-dn.net/?f=t%5E%7B2%7D)
Given that The length of a square's sides begins at 0 cm and increases at a constant rate of 11 cm per second. Assume the function f determines the area of the square (in cm2) given several seconds, t since the square began growing and asked to find the function of the area
Lets assume the length of side of square is x
11 ![\frac{cm}{sec}](https://tex.z-dn.net/?f=%5Cfrac%7Bcm%7D%7Bsec%7D)
⇒x=11t
Area of square=![(length of side)^{2}](https://tex.z-dn.net/?f=%28length%20of%20side%29%5E%7B2%7D)
Area of square=
{as the length of side is 11t}{varies by time}
Area of square=121![t^{2}](https://tex.z-dn.net/?f=t%5E%7B2%7D)
Therefore,The function of the area of the square is A(t)=121![t^{2}](https://tex.z-dn.net/?f=t%5E%7B2%7D)
Learn more about area here:
brainly.com/question/27683633
#SPJ4
Answer:
The last one.
Step-by-step explanation:
Because it is being multiplied in parathenses it means that both the numbers would have to be multiplied.
Answer:
30, 150, 120, and 60 degrees
Step-by-step explanation:
Since the sum of the interior angles in a quadrilateral is 360 degrees:
y+5y+4y+2y=360
12y=360
y=30
2y=60, 4y=120, 5y=150
Hope this helps!