Answer:
<em>The equation of the parallel line to the given equation is </em>
<em>3 x-4 y = -4 and </em>
<em>The equation of the parallel line to the given equation is </em>
<em></em>
Step-by-step explanation:
<u><em>Explanation</em></u>:-
Given equation of the line 3 x -4 y = 7 and given point ( -4 , -2 )
<em>The equation of the parallel line to the given equation is </em>
<em>3 x - 4 y = k </em>
it is passes through the point ( -4 , -2)
3 (-4) - 4 ( -2) = k
-12 +8 = k
k = -4
<em>The equation of the parallel line to the given equation is </em>
<em>3 x- 4 y = -4 </em>
<em>Dividing '4' on both sides , we get</em>
<em></em><em></em>
<em></em><em></em>
<em></em><em></em>
<u><em>Conclusion</em></u>:-
∴ <em>The equation of the parallel line to the given equation is </em>
<em>3 x- 4 y = -4 </em>
<em>and </em>
<em>The equation of the parallel line to the given equation is </em>
<em> </em>
Circle: x^2+y^2=121=11^2 => circle with radius 11 and centred on origin.
g(x)=-2x+12 (from given table, find slope and y-intercept)
We can see from the graphics that g(x) will be almost tangent to the circle at (0,11), and that both intersection points will be at x>=11.
To show that this is the case,
substitute g(x) into the circle
x^2+(-2x+12)^2=121
x^2+4x^2-2*2*12x+144-121=0
5x^2-48x+23=0
Solve using the quadratic formula,
x=(48 ± √ (48^2-4*5*23) )/10
=0.5058 or 9.0942
So both solutions are real and both have positive x-values.