Answer:
The ratio of the areas of the smaller rectangle to the larger rectangle is 
Step-by-step explanation:
we know that
if two figures are similar, then the ratio of its areas is equal to the scale factor squared
Let
z-----> the scale factor
x-----> the area of the smaller rectangle
y----> the area of the larger rectangle
so
substitute the values
simplify
That means, the area of the larger rectangle is 9 times the area of the smaller rectangle
------> the scale factor
That means, the dimensions of the larger rectangle is 3 times the dimensions of the smaller rectangle
The area of a parallelogram is given by
Now, if we consider the 9.9 inches side as the base, then the height is the one labeled with 5.5 inches.
If instead we choose the 11 inches side as the base, the height is h.
So, we can express the area in this two equivalent ways:
Solving for h, we have
Answer:
See below
Step-by-step explanation:
It is NOT a RIGHT triangle so you <u>cannot use</u> 1/2 b * h
but you can use Heron's Formula
Area = sqrt( s (s-a)(s-b)(s-c) )
s = semi- perimeter = (3+6+7)/2 = 8
Area = sqrt ( 8 ( 8-3)(8-6)(8-7) ) = sqrt ( 80) = 8.9 cm^2
The correct answer is option A
y = x² - 4x + 4
0 = x² - 4x + 4
0 = x² - 2x - 2x + 4
0 = x(x) - x(2) - 2(x) - 2(-2)
0 = x(x - 2) - 2(x - 2)
0 = (x - 2)(x - 2)
0 = (x - 2)²
0 = x - 2
+ 2 + 2
2 = x
(x, y) = (2, 0)
