Answer: Triangle ABC and Triangle ECD
Step-by-step explanation:
In Triangle ABC and Triangle ECD
BD=CD and AD=ED [given in the figure]
∠BDA=∠EDC [Vertically opposite angles are equal]
⇒ΔABC ≅ ΔECD [By SAS postulate]
SAS postulate or Side Angle Side postulate tells that if two sides and their included angle of one triangle are congruent to two sides and the included angle of another triangle, then the two triangles are congruent.
3. The leading coefficient of the function f(x)= 3x⁵+6x⁴-x-3 is 3.
For the function f(x)= 3x⁵+6x⁴-x-3 , the highest power of x is 5, so the degree is 5. The leading term is the term containing that degree, 3x⁵. The leading coefficient is the coefficient of that term, 3.
The answer for the question is 2:5
original slope = -4/3
parallel slope = -4/3
Explanation:
For a line to be parallel to anpother line, the slope of both lines must be equal.
We need to find the slope of the given line by picking any two points on the line.
Using points (-6, 5) and (0, -3)
slope formula:


The equation of the given line: y = mx + b
b = y-intercept = -3
y = -4/3x - 3
The equation line parallel to the one above could be:
y = -4/3 x + 7
This because the slope are the same
original slope = -4/3
parallel slope = -4/3
plotting the graph of the lline parallel to the first one: