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zysi [14]
3 years ago
15

On an algebra test, the highest grade was 42 points higher than the lowest grade. The sum of the two grades was 138. Find the lo

west grade.
Mathematics
1 answer:
miv72 [106K]3 years ago
3 0


you could use this equation to help you solve it;

x + (x + 42) = 138

the first step is to combine like terms;

2x = 138 -42

2x = 96

X = 96/2

X = 48

we already solved for x now substitute it in the equation I gave you.

48 + (48 + 42) = 138

48 + 90 = 138

hope it helped...if you have any concerns just let me know:) 

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Decide whether the change is an increase or a decrease, and find the percent change. Original number = 35; New number = 16.... P
Elodia [21]

Answer: 60 decrease or 150 decrease

Step-by-step explanation:

3 0
3 years ago
Write the linear equation from the given information in slope intercept form (-1,3); slope=-3​
nadya68 [22]

Answer:

<h3>y = -3x</h3>

Step-by-step explanation:

The standard expression of equation of a  line in slope-intercept form is expressed as;

y = mx+c

m is the slope

c is the intercept

Given

slope m = -3

Point (x, y) = (-1, 3)

x = -1 and y = 3

Get the intercept

To get the intercept c, we will substitute the given values into the equation above to have;

y = mx+c

3 = -3(-1)+c

3 = 3 + c

c = 3-3

c = 0

Substitute m = -3 and c = 0 into the equation above;

y = mx+c

y = -3x+0

y = -3x

Hence the required linear equation is y = -3x

4 0
3 years ago
7v=2v-20 what is the answer
Ierofanga [76]
7v = 2v - 20

First, subtract 2v from both sides. / Your problem should look like: 7v - 2v = -20
Second, simplify 7v - 2v to 5v. / Your problem should look like: 5v = -20
Third, divide both sides by 5. / Your problem should look like: v = - \frac{20}{5}
Fourth, simplify \frac{20}{5} to 4. / Your problem should look like: v = -4

Answer: v = -4


7 0
3 years ago
I roll a fair die twice and obtain two numbers X1= result of the first roll and X2= result of the second roll. Given that I know
azamat

By definition of conditional probability,

P(X_1=4\text{ or }X_2=4\mid X_1+X_2=7)=\dfrac{P((X_1=4\text{ or }X_2=4)\text{ and }X_1+X_2=7)}{P(X_1+X_2=7)}

=\dfrac{P((X_1=4\text{ and }X_1+X_2=7)\text{ or }(X_2=4\text{ and }X_1+X_2=7))}{P(X_1+X_2=7)}

Assuming a standard 6-sided fair die,

  • if X_1=4, then X_1+X_2=7 means X_2=3; otherwise,
  • if X_2=4, then X_1=3.

Both outcomes are mutually exclusive with probability \frac1{36} each, hence total probability \frac2{36}=\frac1{18}.

Of the 36 possible outcomes, there are 6 ways to sum the integers 1-6 to get 7:

(1, 6), (2, 5), (3, 4), (4, 3), (5, 2), (6, 1)

and so a sum of 7 occurs \frac6{36}=\frac16 of the time.

Then the probability we want is

P(X_1=4\text{ or }X_2=4\mid X_1+X_2=7)=\dfrac{\frac1{18}}{\frac16}=\frac13

6 0
3 years ago
Andrew drives through 5 intersections with stoplights on his way to work. He records that he is stopped by a red light in 2 of t
photoshop1234 [79]

Answer:

He should expect to be stopped a total of 16 times

Step-by-step explanation:

What the question is saying is that out of every 5 intersections, he would be stopped at 2.

Now, for forty times in which he passes through an intersection , we want to know the number of times in which he would be stopped

In this case we only need to multiply the probability by the number of times in which he passes an intersection and that would be 2/5 * 40 = 16 times

4 0
3 years ago
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